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Help with Bash script - set, awk

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Top Forums Shell Programming and Scripting Help with Bash script - set, awk
# 8  
Old 07-13-2009
Sorry for buggin u..
I still get the same error

$ echo $pat1
Processing
$ echo $pat2
aaaa
$ cat test
asdsf

aaaa

adsajd

asda



Processing



sdfdkjf

aaaa

dflkjd

dfjkhdk


$ awk '/p1/{f=1} f && /p2/{print;end}' p1=$pat1 p2=$pat2 test
awk: syntax error near line 1
awk: bailing out near line 1
$

---------- Post updated at 08:23 AM ---------- Previous update was at 08:20 AM ----------

Sorry, I dont get the error, But I dont get the desired output


$ echo $pat1
Processing
$ echo $pat2
aaaa
$ cat test
asdsf

aaaa

adsajd

asda



Processing



sdfdkjf

aaaa

dflkjd

dfjkhdk


$ nawk '/p1/{f=1} f && /p2/{print;end}' p1=$pat1 p2=$pat2 test
$ /usr/xpg4/bin/awk '/p1/{f=1} f && /p2/{print;end}' p1=$pat1 p2=$pat2 test
# 9  
Old 07-13-2009
I'm sorry, the code should be:

Code:
nawk '$0 ~ p1{f=1} f && $0 ~ p2{print;end}' p1=$pat1 p2=$pat2 test.dat

# 10  
Old 07-13-2009
Hi Thanks a lot.
$ /usr/xpg4/bin/awk '$0 ~ p1{f=1} f && $0 ~ p2{print;end}' p1=$pat1 p2=$pat2 subha
input file "Started"aaaa
aaaa
$

I get " input file "Started" " in the output. Can we omit this and just print aaaa??

Thanks for your help!
# 11  
Old 07-13-2009
Strange..try this, assuming subha is the filename:

Code:
/usr/xpg4/bin/awk -v p1=$pat1 -v p2=$pat2 '$0 ~ p1{f=1} f && $0 ~ p2{print;end}' subha

# 12  
Old 07-13-2009
When I run the command, it prompts as below...
$ /usr/xpg4/bin/awk -v p1=$pat1 -v p2=$pat2 '$0 ~ p1{f=1} f && $0 ~ p2{print;end}' file
input file "-v"$ Started
ksh: Started: not found

I am not sure either..
# 13  
Old 07-13-2009
I don't know what's wrong, the code seems to be correct, post a part of the original file and the desired output within code tags.

Regards
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