awk question


 
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# 1  
Old 05-08-2008
awk question

I'm writing a script that gets and removes all directories except for certain predefined ones. I'm currently using awk, but I admit that I'm not terribly comfortable with it. My current code works for directories that don't contain any spaces, but for those that do, it just passes the final word to rm, which obviously means that rm won't find it.


Code:
dirsToDelete=`ls -l|awk 'NF>2 &&!/Desktop/&&!/Documents/&&!/Library/&&!/Movies/&&!/Music/&&!/Pictures/&&!/Public/&&!/Sites/{print $NF}'`
for dir in $dirsToDelete; do
    rm -r $dir
done


Any ideas?
# 2  
Old 05-08-2008
Change the IFS temporary, something like:

Code:
OIFS=$IFS
IFS=""
dirsToDelete=`ls -l|awk 'NF>2 &&!/Desktop/&&!/Documents/&&!/Library/&&!/Movies/&&!/Music/&&!/Pictures/&&!/Public/&&!/Sites/{print $NF}'`
for dir in $dirsToDelete; do
    rm -r $dir
done
IFS=$OIFS

Regards

Last edited by Franklin52; 05-08-2008 at 02:27 PM..
# 3  
Old 05-08-2008
Sorry, that doesn't do it. Still only returns the last word of multi-word folders.
# 4  
Old 05-08-2008
It can all be done within a single awk script so the for loop is of no use and replace ls -l (ell) with ls -1 (one)
Code:
ls -1 | awk 'NF>2 &&!/Desktop/&&!/Documents/&&!/Library/&&!/Movies/&&!/Music/&&!/Pictures/&&!/Public/&&!/Sites/{system("rm -r \""$0"\"")}'

# 5  
Old 05-08-2008
That did it. Thanks so much!
# 6  
Old 05-08-2008
...

[ksh]

Code:
rm -r -- !(Desktop|Documents|Library|Movies|Music|Pictures|Public|Sites)/

[bash]

Code:
shopt -s extglob
rm -r -- !(Desktop|Documents|Library|Movies|Music|Pictures|Public|Sites)/

[zsh]

Code:
setopt extendedglob
rm -r -- ^(Desktop|Documents|Library|Movies|Music|Pictures|Public|Sites)/

# 7  
Old 05-08-2008
radoulov:
I used your bash version, which works fine until it encounters one of the folders defined within the parentheses, at which point execution terminates and "kj#: command not found" is spit out. What's this mean/how do I get it to go away?
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