JSONBOT(1) jsb manual JSONBOT(1)NAME
JSONBOT - The JSON everywhere bot!
SYNOPSIS
JSONBOT is a remote event-driven framework for building bots that talk JSON to each other over XMPP. This manual page documents briefly the
jsb distribution..
DESCRIPTION
This distribution provides bots built on this framework for console, IRC, XMPP, Convore and WWW on the shell.
USAGE
JSONBOT uses command line options to configure a bot. See the --help option to get more help on a command options or see the corresponding
man page.
the jsb pakage contains the following programs:
* jsb - console version of jsb
* jsb-backup - create backup of JSONBOT datadir
* jsb-convore - convore version of jsb
* jsb-init - create data directory and config examples, default ~/.jsb
* jsb-irc - IRC version of jsb
* jsb-fleet - mix IRC and XMPP bots
* jsb-sed - sed a whole directory
* jsb-stop - stop a running bot
* jsb-tornado - a shell web server based on tornado
* jsb-udp - send udp packets to the bot that will relay the data
* jsb-xmpp - XMPP version of jsb
note: JSONBOT is in BETA stage right now and still subject to change of protocols and API.
see http://jsonbot.googlecode.com. see https://jsonbot.org for documentation on the bot.
SEE ALSO
The program is documented fully on http://jsonbot.org or see http://jsonbot.googlecode.com
SEE ALSO jsb(1), jsb-backup(1), jsb-init(1), jsb-irc(1), jsb-xmpp(1), jsb-fleet(1), jsb-tornado(1), jsb-stop(1), jsb-udp(1)AUTHOR
This manual page was written by Bart Thate <bthate@gmail.com>, for the Debian GNU/Linux system (but may be used by others).
Debian GNU/Linux 22 Nov 2011 JSONBOT(1)
Check Out this Related Man Page
RBOT(1) rbot man page RBOT(1)NAME
rbot - IRC bot written in ruby
SYNOPSIS
rbot [{[-d] | [--debug]} {[-h] | [--help]} {[-v] | [--version]} {[-l LEVEL] | [--loglevel LEVEL]} {[-b] | [--background]} {[-p PIDFILE] |
[--pidfile PIDFILE]}] [confdir]
DESCRIPTION
rbot starts the Rbot (ruby IRC bot).
OPTIONS
This program follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is included
below.
-d, --debug
Display debug information (very verbose).
-h, --help
Show summary of options.
-v, --version
Display version information.
-l LEVEL, --loglevel LEVEL
Sets the minimum log level verbosity. Possible values for the loglevel are 0 (DEBUG), 1 (INFO), 2 (WARN), 3 (ERROR), 4 (FATAL). The
default loglevel is 1 (INFO messages). The logfile is located at BOTDIR/BOTNAME.log and doesn't contain IRC logs (which are located at
BOTDIR/logs/*), but only rbot diagnostic messages.
-b, --background
Background (daemonize) the bot.
-p PIDFILE, --pidfile PIDFILE
Write the bot pid to PIDFILE. The default pidfile is BOTDIR/rbot.pid.
BOTDIR
Path to the directory where are stored the bot's configuration files. The default config directory is ~/.rbot.
VERSION
This manual page was written by Marc Dequenes (Duck) Duck@DuckCorp.org for the Debian(TM) system (but may be used by others). Permission is
granted to copy, distribute and/or modify this document under the terms of the GNU General Public License, Version 3 or any later version
published by the Free Software Foundation.
On Debian systems, the complete text of the GNU General Public License can be found in /usr/share/common-licenses/GPL.
AUTHORS
Marc Dequenes <Duck@DuckCorp.org>
Debian(TM) package maintainer
Giuseppe Bilotta <giuseppe.bilotta@gmail.com>
rbot maintainer
COPYRIGHT
Copyright (C) 2004-2009 Marc Dequenes (Duck)
Copyright (C) 2010 Giuseppe Bilotta
rbot 0.9.15 20100701 RBOT(1)
hi
I am using "sed" command to find and replace a text in a file.
if the searched string is in the last line with no newline character in the end, it doesn't retrive this line. What is the solution to this?
i am using sed as:
sed -e "s/abc/ABC/g" test.txt
where i am replacing abc with ABC (11 Replies)
i tried the following:-
sed -e file 's/^@//g' > temp
also tried
sed -e file 's///g' > temp
nothing happened....can someone please tell me wht is wrong???
also someinformation abt the character "^@"(it is ONLY ONE character and NOT TWO characters)
thanx in advance.. (13 Replies)
Hello
My file looks like that =>
12.56 have then 7888778.2566 what 44454.54545
878787.66565 if else 4445.54545455
I want to change all '.' on ',' .
I'm trying to do it with sed but I don't know chow to build regular expression to
change 454.4466 on 454,4466 ? (13 Replies)
in a bash shell I have the following
S00="BLOCK-NAMES /ELM1 /SAUT0 /FIT00 FOR ELMT,SAMPLE,FIT"
S01="BLOCK-NAMES /ELM1 /SAUT0 /FIT01 FOR ELMT,SAMPLE,FIT"
sed "s/'$S00'/'$S00'/g" pb206.cnt > tmp
sed commplains and says
sed: -e expression #1, char 29: Unknown... (11 Replies)
Hi falks,
I need to dispaly a list of only directories .
As it written in the manual ,the command to do it is 'ls -d'.
When i issue 'ls -d' i'm getting:
tornado.orca.ent:DB10g :/home/oracle/Create_Database > ls -d
.
Is anyone have any idea why id does not display directories ,or maybe... (11 Replies)
Hello All,
I have a csv file with 3 columns. The file which looks like this
47850000,100,233
23560000,10000,456
78650000,560000,54
34000000,3456,3
The first column has 4 trailing zeros. I have to remove 4 trailing zeroes from 1st field. The output file should appear as follows.
... (12 Replies)
Hi,
What sed command (if sed is the right command) can remove ALL white space from my file. I have a csv, except I want to remove all white space between commas and characters.
My idea (without testing)
sed 's/ //g'
Is there a better way? (18 Replies)
Hi,
Below is the code. The issue is exact value of echo $URL is not replaced in sed in side the function. Any hints..
#!/bin/bash
envurls()
{
URL=`cat temp.txt | sed -e 's%\/%\\\/%g' | grep client.url |cut -d "=" -f 2`
echo $URL
sed 's#CLIENTURL#'$URL'#' temp1.properties>temp &&... (10 Replies)
Hello i am trying to remove the html format from the file using sed. for example remove <p> </p>
i tried to do this : sed -e 's/<*>//g' test > test.t
but still i have some html format . please help if you have any suggestions
lets say this is the html file
1... (11 Replies)
Hi,
can some one suggest me,how "sed" is managed to delete the second field here.
Any explanation on , how the below code is working would be appreciated.
sed 's/^\(*\)::/\1::/' /etc/passwd
sed 's/*:/:/2' /etc/passwd (14 Replies)
I have a string 1234567890
My requirement is to replace the characters between position 6 and 8 (both positions inclusive)
with a string KUMARJIT
i.e.,
1234567890 should change to 12345KUMARJIT90
I am using korn shell and linux 2.6x OS , and I want to do it using sed.
I made it till this... (11 Replies)
Hello All,
I need help with the below, I would appreciate any tip.
I have a file as below
Input file
Apple: Green
Banana: Yellow
Grapes: Black
Apple: Red
Banana: Green
Grapes: Green
Grapes: Brown
Apple: Pale Red
Banana: Greenish yellow
Grapes: Brown
Apple: Yellowish... (14 Replies)
Greetings!
Well, this next example should be a snap, but, instead, sed is raising yet another bump on my head. Here's the "offending" commandline today:sed -i s'/\$\{HOUSING\}/casing/g' ./some.fileAnd, here's the output:sed: -e expression #1, char 27: Invalid content of \{\}FWIW, I tried... (17 Replies)
Hi All,
I am trying to use sed command inside a shell script.
The same sed command is working on command line, however its not working while using inside a shell script.
From various sources i found , it could be done by using -i option, but its not working as well.
sed... (11 Replies)