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# 1  
Old 05-08-2015
Daily averages...

I have date file like below..
1995   1       2      10      29      38.6706     -6.53823      41.9201
1995   1       2      10      29     -49.2477     -4.59733      17.2704
1995   1       2      10      29     -49.2369     -4.48045      8.61348
1995   1       3       8       48     -42.2643     -5.37043      28.9973
1995   1       3       8      48     -33.9019     -4.26548      90.1121

where columns are year, month, day, hour, minute log_val, lat_val, area. I want to find the daily average of area and the output should be like
1995 1 2 10 29 22.601

and so on. how to do using awk or some other linux commands ?

Moderator's Comments:
Mod Comment fixed code tags

Moderator's Comments:
Mod Comment
Please wrap all code, files, input & output/errors in CODE tags as described in the forum rules.
It makes it far easier to read and preserves multiple spaces where that is important to fixed width output.

Last edited by Don Cragun; 05-08-2015 at 04:03 PM.. Reason: Added CODE tags
# 2  
Old 05-08-2015
Is this a homework assignment?

What have you tried so far?
This User Gave Thanks to Don Cragun For This Post:
# 3  
Old 05-10-2015
Moderator's Comments:
Mod Comment Until the question about this being a homework item is resolved; please do not post ways to solve this problem.

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