224.192.48.0/20
is in CIDR format. It's the equivalent to subnet 224.192.48.0 with a netmask of 255.255.240.0. A netmask is always a sequence of 1-bits's followed by a sequence of 0-bit's. The subnet mask 255.255.240.0 has 20 1-bit's. The notation 224.192.48.0/20 is so much more compact than "224.192.48.0 with a netmask of 255.255.240.0" that lots of us just use it all the time even on internal networks that don't involve CIDR.
To split a network 50-25-25 we need to crack it into 4 pieces. That way we can give 2 pieces to the one big guy and then the little guys get one piece each. Notice that 4 is a power of two. It's gotta be that way. If these 3 guys each wanted one third of the network we would be outta luck.
The guy with two pieces can fold them together (or aggregate) them. To do that he needed either the first two or the second two pieces. You can't just give him any random selection.
The 4 way split involved added two more 1-bits's to the subnet mask.
That 4-3-1 split you ask about happens to be possible. So it is probably an assignment.
You will need to crack the network into 8 pieces to start. One guy will get 4 pieces, the next guy gets 3 pieces, and the last guy only gets one piece. The guy with 4 pieces can get all 4 folded back into a single CIDR spec. Not's not the case with the guy who gets 3 pieces. You can fold his first two back together, but then he a final separate piece. That's the way it has to be. The guy with one piece has nothing to fold.