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Homework and Emergencies Emergency UNIX and Linux Support cat issue
# 1  
Old 09-23-2009
cat issue

I have list of files in my current directory

abc.txt
123.csv
234.csv
245.csv
145.csv
123_ex_c.sv

I don't want to open first and last file. i.e (abc.txt and 123_ex_csv)
I tried
cat [0-9]*.csv, but it won't work.
Can anyone tell me the proper regex only in cat

Thanks
Pritish

---------- Post updated at 01:16 PM ---------- Previous update was at 01:03 PM ----------

I know, u people are very busy. It's an issue. Please cooperate me.
# 2  
Old 09-23-2009
Try
Code:
cat [0-9][0-9][0-9].csv

# 3  
Old 09-23-2009
cat $(ls | grep '[0-9].csv' ) will this work ... or you need one command only ? Ignoring anything char ..

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