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Full Discussion: cp & sed error
Top Forums Shell Programming and Scripting cp & sed error Post 98118 by vino on Monday 6th of February 2006 09:18:00 AM
Old 02-06-2006
Quote:
Originally Posted by n8575
Code:
for i in `ls $ORACLE_BASE/admin/${dest}/pfile/`
do
  echo "replacing ${src} to ${dest} for $i"
  cp $i $ORACLE_BASE/admin/${dest}/pfile/$i_backup
  cat $i_backup | sed -e "/s/${src}/${dest}/g" > $i
  rm -f $i_backup
done


cp: cannot access init.ora.162006124556
sed: command garbled: /s/db1/db2/g

Can someone let me know what's wrong with my code, and help me solve the problem?
Thanks!
Remove the / before "/s/..." and enclose all the names within " "

Try this.

Code:
for i in `ls -1 $ORACLE_BASE/admin/${dest}/pfile/`
do
  echo "replacing ${src} to ${dest} for $i"
  cp "$i" "$ORACLE_BASE/admin/${dest}/pfile/$i_backup"
  sed -e "s/${src}/${dest}/g"  "$i_backup" > $i
  rm -f "$i_backup"
done

 

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LEARN ABOUT LINUX

memmove

MEMMOVE(3)						     Linux Programmer's Manual							MEMMOVE(3)

NAME

       memmove - copy memory area

SYNOPSIS

       #include <string.h>

       void *memmove(void *dest, const void *src, size_t n);

DESCRIPTION

       The  memmove()  function  copies  n  bytes  from memory area src to memory area dest.  The memory areas may overlap: copying takes place as
       though the bytes in src are first copied into a temporary array that does not overlap src or dest, and the bytes are then copied  from  the
       temporary array to dest.

RETURN VALUE

       The memmove() function returns a pointer to dest.

CONFORMING TO

       SVr4, 4.3BSD, C89, C99, POSIX.1-2001.

SEE ALSO

       bcopy(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)

COLOPHON

       This  page is part of release 3.27 of the Linux man-pages project.  A description of the project, and information about reporting bugs, can
       be found at http://www.kernel.org/doc/man-pages/.

GNU
								    1993-04-10								MEMMOVE(3)
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