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Full Discussion: Nawk Split
Top Forums UNIX for Dummies Questions & Answers Nawk Split Post 97347 by zazzybob on Sunday 29th of January 2006 06:18:39 AM
Old 01-29-2006
Use eval again...
Code:
a=1
while (( $a <= $setIdx ))
do
  eval "echo \${set$a[@]}"
  (( a += 1 ))
done
exit 0

Cheers
ZB
 

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ARRAY_INTERSECT_ASSOC(3)						 1						  ARRAY_INTERSECT_ASSOC(3)

array_intersect_assoc - Computes the intersection of arrays with additional index check

SYNOPSIS
array array_intersect_assoc (array $array1, array $array2, [array $...]) DESCRIPTION
array_intersect_assoc(3) returns an array containing all the values of $array1 that are present in all the arguments. Note that the keys are used in the comparison unlike in array_intersect(3). PARAMETERS
o $array1 - The array with master values to check. o $array2 - An array to compare values against. o $... - A variable list of arrays to compare. RETURN VALUES
Returns an associative array containing all the values in $array1 that are present in all of the arguments. EXAMPLES
Example #1 array_intersect_assoc(3) example <?php $array1 = array("a" => "green", "b" => "brown", "c" => "blue", "red"); $array2 = array("a" => "green", "b" => "yellow", "blue", "red"); $result_array = array_intersect_assoc($array1, $array2); print_r($result_array); ?> The above example will output: Array ( [a] => green ) In our example you see that only the pair "a" => "green" is present in both arrays and thus is returned. The value "red" is not returned because in $array1 its key is 0 while the key of "red" in $array2 is 1, and the key "b" is not returned because its values are different in each array. The two values from the key => value pairs are considered equal only if (string) $elem1 === (string) $elem2 . In other words a strict type check is executed so the string representation must be the same. SEE ALSO
array_intersect(3), array_uintersect_assoc(3), array_intersect_uassoc(3), array_uintersect_uassoc(3), array_diff(3), array_diff_assoc(3). PHP Documentation Group ARRAY_INTERSECT_ASSOC(3)
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