memcpy segfaults, but not in windows Post: 95625

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Top Forums Programming memcpy segfaults, but not in windows Post 95625 by cjediknight on Thursday 12th of January 2006 08:16:55 PM

01-12-2006

Registered User

Yes I think your problem is the buffer variable, where dir you define it and how did you define it,

if you just defined it in a global variable like this,

char * buffer, then definetely you have a problem or they are right the buffer would be too small..

It run in windows because I experience some window based C/C++ compiler allow you to access memory that was not allocated or that is not belongs to you.

cjediknight

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memcpy

MEMCPY(3)						     Linux Programmer's Manual							 MEMCPY(3)

NAME

       memcpy - copy memory area

SYNOPSIS

       #include <string.h>

       void *memcpy(void *dest, const void *src, size_t n);

DESCRIPTION

       The  memcpy()  function copies n bytes from memory area src to memory area dest.  The memory areas must not overlap.  Use memmove(3) if the
       memory areas do overlap.

RETURN VALUE

       The memcpy() function returns a pointer to dest.

CONFORMING TO

       SVr4, 4.3BSD, C89, C99, POSIX.1-2001.

SEE ALSO

       bcopy(3), memccpy(3), memmove(3), mempcpy(3), strcpy(3), strncpy(3), wmemcpy(3)

COLOPHON

       This page is part of release 3.44 of the Linux man-pages project.  A description of the project, and information about reporting bugs,  can
       be found at http://www.kernel.org/doc/man-pages/.

								    2010-11-15								 MEMCPY(3)