10-22-2001
Recon thank you,
However this doesn't hold the year, how can I determine the year?
The 'stat' command is not available on this server.
I can assign the modification date to a variable like this :
moddate = 'ls -l file |awk '{print $6 $7 }''
So if moddate = Oct18, I have to convert it to 101801.
How can that be accomplished in an efficient way?
Last edited by jamesbond; 10-22-2001 at 06:04 AM..
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LEARN ABOUT PHP
datetime.format
DATETIME.FORMAT(3) 1 DATETIME.FORMAT(3)
DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTime.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO
date(3).
PHP Documentation Group DATETIME.FORMAT(3)