If I have string { I_love_shell_scripts}
anyone knows how to have output {stpircs_llehs_evol_I}
by using shell and perl ?I know in perl, there is reverse() funcation, but
can it be done by not using reverse()? (3 Replies)
Hi Everyone....I am new to Unix and BASH programming...I just want to read a string and reverse it and display.....can anyone help me out???? (8 Replies)
Hello
I am currently working on a shell script which actually needs to pull some file
from a server ,
The filenames will have the extension with date/time stamp , i need to trim that and name it to proper format
Example :
xyz_20091108_22142365.gzip
i need to remove the... (5 Replies)
FOLKS ,
i have a text file that is generated automatically of an another korn shell script, i want to bring in the fifth line of the text file in to my korn shell script and look for a particular word in the line . Can you all share some thoughts on this one.
thanks...
Venu (3 Replies)
I am reading a string like $/folder1/folder2/filename from a file
And I am storing it in a variable say $path.
I want to store the path within single quotes in order to use the path within a command.
if i set like path="'"$path"'"
echo $path
It is printing like ' $/folder1/folder2/filename'... (6 Replies)
Hello all,
Wondering if anyone can help me out.
Trying to cut the names out of the /etc/passwd file so that they can be displayed first then last name. I cut them out and put them into variables but cant get them to display side by side after cutting. Anyone able to help a newbie? (1 Reply)
i used a two-way linked list "node" for the code::
#include<stdio.h>
#include<malloc.h>
void insert();
void reverse();
struct node
{
char c;
struct node *next;
struct node *back;
}*start=NULL;
int main()
{
int n,i; (4 Replies)
Hi,
I am stuck at comparing a value from database with a space involved.
Condition
if (cust_code != "RAMK" && cust_code != "LML")
{
xxxxxxx
xxxxxxx
xxxxxxx
}
the cust_code is from a table and generally has 4 chars...so in the case of LML it comes with default space at the end.
... (1 Reply)
HI,
I have a string "NZ-deploy-mode-1.15-Linux.x86_64.rpm"
I want to get the string before -1 ie "NZ-deploy-mode"
Input is "NZ-deploy-mode-1.15-Linux.x86_64.rpm"
expected output is "NZ-deploy-mode"
How can I do that in shell script?
Thanks in advance. (6 Replies)
Hi,
I wish to grep everything before the last "/bin" in the following string
/opt/app/bin/app1/jdk150_07/bin/IA64N/java
Desired output: "/opt/app/bin/app1/jdk150_07"
Kindly help ... (2 Replies)
Discussion started by: mohtashims
2 Replies
LEARN ABOUT REDHAT
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)