09-15-2005
sort data
Hi!
I'm trying to sort a file.dat with the sort command. The data contained by file.dat is similar to the data set below:
100.000
99.000
110.000
55.000
113.000
33.000
25.000
9.000
15.000
It is relatively easy to sort the data in ascending or descending order, but the problem is that the separating empty rows between the blocks are put on top of the sorted file. I wish to keep the empty rows and sort the data blocks separately, like this:
99.000
100.000
110.000
33.000
55.000
113.000
9.000
15.000
25.000
Can anybody please help me?
And also I must mention that I'm quite new at UNIX scripting, so try to explain in plain English
!
bjorb
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LEARN ABOUT MOJAVE
ualarm
UALARM(3) BSD Library Functions Manual UALARM(3)
NAME
ualarm -- schedule signal after specified time
LIBRARY
Standard C Library (libc, -lc)
SYNOPSIS
#include <unistd.h>
useconds_t
ualarm(useconds_t useconds, useconds_t interval);
DESCRIPTION
This is a simplified interface to setitimer(2).
The ualarm() function waits a count of useconds before asserting the terminating signal SIGALRM. System activity or time used in processing
the call may cause a slight delay.
If the interval argument is non-zero, the SIGALRM signal will be sent to the process every interval microseconds after the timer expires
(e.g., after useconds number of microseconds have passed).
Due to a setitimer(2) restriction, the maximum number of useconds and interval is limited to 100,000,000,000,000 (in case this value fits in
the unsigned integer).
RETURN VALUES
When the signal has successfully been caught, ualarm() returns the amount of time left on the clock.
NOTES
A microsecond is 0.000001 seconds.
SEE ALSO
getitimer(2), setitimer(2), sigpause(2), sigvec(2), alarm(3), signal(3), sleep(3), usleep(3)
HISTORY
The ualarm() function appeared in 4.3BSD.
BSD
April 19, 1994 BSD