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Top Forums Shell Programming and Scripting Problem in assigning values to variables Post 81920 by mohanprabu on Thursday 25th of August 2005 04:44:07 AM
Old 08-25-2005
Bug

Quote:
Originally Posted by rein
using arrays you can do this:

#initialise i
i=0

#initialise input
input=test

#assign $input to specified array element
temp[$i]=$input

#echo array value at pos i
echo ${temp[i]}
Thanks rein.. (apologies for late reply)..

This method is now working fine.. Never realized the concepts of arrays.. Smilie

Thanks aigles ..
 

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FORWARD_STATIC_CALL(3)							 1						    FORWARD_STATIC_CALL(3)

forward_static_call - Call a static method

SYNOPSIS
mixed forward_static_call (callable $function, [mixed $parameter], [mixed $...]) DESCRIPTION
Calls a user defined function or method given by the $function parameter, with the following arguments. This function must be called within a method context, it can't be used outside a class. It uses the late static binding. PARAMETERS
o $function - The function or method to be called. This parameter may be an array, with the name of the class, and the method, or a string, with a function name. o $parameter - Zero or more parameters to be passed to the function. RETURN VALUES
Returns the function result, or FALSE on error. EXAMPLES
Example #1 forward_static_call(3) example <?php class A { const NAME = 'A'; public static function test() { $args = func_get_args(); echo static::NAME, " ".join(',', $args)." "; } } class B extends A { const NAME = 'B'; public static function test() { echo self::NAME, " "; forward_static_call(array('A', 'test'), 'more', 'args'); forward_static_call( 'test', 'other', 'args'); } } B::test('foo'); function test() { $args = func_get_args(); echo "C ".join(',', $args)." "; } ?> The above example will output: B B more,args C other,args SEE ALSO
forward_static_call_array(3), call_user_func_array(3), call_user_func(3), is_callable(3), information about the callback type. PHP Documentation Group FORWARD_STATIC_CALL(3)
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