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Top Forums UNIX for Dummies Questions & Answers Trying to capture empty variable. Post 79274 by radhika on Tuesday 26th of July 2005 01:54:59 PM
Old 07-26-2005
I got it....

filedate=`ls -al test.txt | cut -f2-3 -d'0' | cut -f1-4 -d' ' `
echo $filedate

date=$filedate
dte=`date +%Y%m%d%H%M%S`
echo $dte

Result is:
20050726135232

Thanks! Vino for the idea.
Regards,
Radhika.
 

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DATETIMEIMMUTABLE.FORMAT(3)						 1					       DATETIMEIMMUTABLE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTimeImmutable.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIMEIMMUTABLE.FORMAT(3)
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