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Full Discussion: C snipet on char Pointers
Top Forums Programming C snipet on char Pointers Post 79223 by infierno on Tuesday 26th of July 2005 09:19:40 AM
Old 07-26-2005
It is syntactically valid, the compiler doesn't complain because the syntax is correct in that code, but... wha't really happens there:

char *p; only allocates the sufficient memory to hold the address of the pointer but not the rest elements of the "array". What this really means?, you have a char type pointer with 4 bytes allocated but a string with more than 15 characters.

As result you will have a run time error commonly known as memory fault access, the application receives a SIGSEGV (typically Memory fault or Segmentation fault message on you shell) signal and terminates instantly.

To solve this, you should allocate memory for your string with malloc() or statically initialize the pointer doing char *p=" I am a Very good boy";

using malloc() it maybe shows like this:

char *p;

p = (char *) malloc( (size_t) 20);

sprintf(p, "%s", "I'm a very good boy");


Best regards!

Last edited by infierno; 07-26-2005 at 10:40 AM..
 

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bsdmalloc(3MALLOC)                                                                                                              bsdmalloc(3MALLOC)

NAME
bsdmalloc - memory allocator SYNOPSIS
cc [ flag ... ] file ... -lbsdmalloc [ library ... ] char *malloc(size); unsigned size; int free( ptr); char *ptr; char *realloc( ptr, size); char *ptr; unsigned size; These routines provide a general-purpose memory allocation package. They maintain a table of free blocks for efficient allocation and coa- lescing of free storage. When there is no suitable space already free, the allocation routines call sbrk(2) to get more memory from the system. Each of the allocation routines returns a pointer to space suitably aligned for storage of any type of object. Each returns a null pointer if the request cannot be completed. The malloc() function returns a pointer to a block of at least size bytes, which is appropriately aligned. The free() function releases a previously allocated block. Its argument is a pointer to a block previously allocated by malloc() or real- loc(). The free() function does not set errno. The realloc() function changes the size of the block pointed to by ptr to size bytes and returns a pointer to the (possibly moved) block. The contents will be unchanged up to the lesser of the new and old sizes. If the new size of the block requires movement of the block, the space for the previous instantiation of the block is freed. If the new size is larger, the contents of the newly allocated portion of the block are unspecified. If ptr is NULL, realloc() behaves like malloc() for the specified size. If size is 0 and ptr is not a null pointer, the space pointed to is freed. The malloc() and realloc() functions return a null pointer if there is not enough available memory. They return a non-null pointer if size is 0. These pointers should not be dereferenced. When realloc() returns NULL, the block pointed to by ptr is left intact. Always cast the value returned by malloc() and realloc(). If malloc() or realloc() returns unsuccessfully, errno will be set to indicate the following: ENOMEM size bytes of memory cannot be allocated because it exceeds the physical limits of the system. EAGAIN There is not enough memory available at this point in time to allocate size bytes of memory; but the application could try again later. Using realloc() with a block freed before the most recent call to malloc() or realloc() results in an error. Comparative features of the various allocation libraries can be found in the umem_alloc(3MALLOC) manual page. brk(2), malloc(3C), malloc(3MALLOC), mapmalloc(3MALLOC), umem_alloc(3MALLOC) WARNINGS
Use of libbsdmalloc renders an application non-SCD compliant. The libbsdmalloc routines are incompatible with the memory allocation routines in the standard C-library (libc): malloc(3C), alloca(3C), calloc(3C), free(3C), memalign(3C), realloc(3C), and valloc(3C). 21 Mar 2005 bsdmalloc(3MALLOC)
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