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Full Discussion: need grep to output basename and line#
Top Forums Shell Programming and Scripting need grep to output basename and line# Post 78053 by zoo591 on Friday 15th of July 2005 02:23:19 AM
Old 07-15-2005
Question need grep to output basename and line#
I have a script that sorta works the way I want but I would rather
just get the base name and line number from the grep output.

My current script is this one liner:

grep -n "$1" $SCCSPATH/*/s.*.k | cut -c1-80

which if I was searching for 121197 I would get something like this:

/versyss/data/devel/src/prsrc/2.20/vs220/s.195pr.k:2000:* fix 121197

I would rather get something like this from my grep output:
s.195pr.k:2000:* fix 121197

Any ideas how this can be done (non perl answers only please)

TIA
Zoo591
 

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LEARN ABOUT NETBSD

zegrep

ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME

     zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files

SYNOPSIS

     zgrep [grep-flags] [--] pattern [files ...]

     zegrep [grep-flags] [--] pattern [file ...]

     zfgrep [grep-flags] [--] pattern [file ...]

DESCRIPTION

     zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).

     The grep-flags and pattern arguments are passed on to grep(1).  If an -e flag is found in the grep-flags, zgrep will not look for a pattern
     argument.

     zegrep calls egrep(1), while zfgrep calls fgrep(1).

EXIT STATUS

     In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.

SEE ALSO

     egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)

AUTHORS

     Thomas Klausner <wiz@NetBSD.org>

BSD
								 December 28, 2003							       BSD
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