I have to add a variable value to an array, something like this:
......
@my_array_name = $value_of_this_variable;
This doesnt seem to work, any ideas why?
Thanks! (4 Replies)
hi every body,
i donot know how to assign a array varible with a file
see i having file
more file
property1 Name
property2 Address
the above two line are tab Space seperated between the property and its value
i want to seperate it and assign to... (1 Reply)
I need to do something like this:
for i in 1 2 3 4 5; do
arr=$(awk 'NR="$i" { print $2 }' file_with_5_records)
done
That is, parse a file and assign values to an array in an ascending order relative to the number of record in the file that is being processed on each loop.
Is my... (2 Replies)
Hello,
Can somebody please give me a snippet for the below requirement.
I want to assign the values separeted by a comma to be assigned to a dynamic array.
If I give an input (read statement) like abc1,abc2,abc3,abc4,abc5, all these strings abc* should be assigned to an array like below... (2 Replies)
set -A matched #find referenced files.
for i in ${file_names_html}
do
counter_j=0
for j in ${file_names_minus_index}
do
match=`cat $i | grep... (1 Reply)
hi
My script as below
#!/bin/ksh
for i in `seq 1 7`
do
a=$(awk '{print $i}' /home/rama/expenese.txt)
done
for i in `seq 1 7`
do
echo "${a}"
done
content of expense.txt is as below
5032 210179 3110 132813874 53488966 11459221 5300794
I want output as... (6 Replies)
Hi ,
i have file which is having two fields in it (#delimited)
ABC#FILE_01.DAT
DEF#FILE_02.DAT
i want to write first field values to one array example A_01 and second field values to B_02 array
please let me know how to do this ,my final requirement i have send out a mail for each record... (2 Replies)
I want to extract each and single character from a password string and put it in an array.
I tried this :
set -A password "echo $passwd | awk '{for (i=1; i<=length($1); i++) printf "%s ",substr($1,i,1)}'`
It's working as long that the password string doesn't contains any *
I tried a few... (5 Replies)
Hi,
I have the following code that makes use of a URL that I store in a variable then create a document object below to work on it.
$dom = new DOMDocument;
@$dom->loadHTML($html);
$links = $dom->getElementsByTagName('a');
$links = $dom->getElementsByTagName('a');
... (0 Replies)
Discussion started by: mojoman
0 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)