Sponsored Content
Top Forums Shell Programming and Scripting Passing output of sed/echo to a variable Post 77854 by zazzybob on Wednesday 13th of July 2005 09:29:52 AM
Old 07-13-2005
No probs Smilie

I think I see the problem....

I didn't use code tags and maybe the backticks look like single quotes if you haven't copied and pasted directly....

Code:
set j = `echo "$i" | sed "s/$1/$2/"`

Cheers
ZB
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

variable passing to sed

I m trying to pass variable to sed. export var=140920060731 sed -e '/$var/d' file but no luch so far..? any body has any idea abt it Is there any way to pass variable to SED? Thanks , Manish (2 Replies)
Discussion started by: Manish Jha
2 Replies

2. Shell Programming and Scripting

Passing output to variable instead of file

Hi, In normal shell scripting, how do you pass the output of a command to a variable, instead of a file and be able to use it later? The code is: #!/bin/bash who | cut -d" " -f1 > onlineusers Instead of passing the output of the above command to the file called 'onlineusers'... (1 Reply)
Discussion started by: Furqan_79
1 Replies

3. Shell Programming and Scripting

Passing Variable in sed

Dear All, I want to print a file. First I tried with this sed '2q;d' filename it worked. But when i put following it is not working x=2; sed '$xq;d' filename Would any one suggest how to pass the variable? (7 Replies)
Discussion started by: saifurshaon
7 Replies

4. Shell Programming and Scripting

storing output from echo & cut into variable

Hi All, Hope someone can advise here as I have been struggling to find a syntax that works here. I have tried a stack of combination I have seed in the forums but I think because I have needed to use "" and `` in the statments another method is found. I am reading in lines with the following... (1 Reply)
Discussion started by: nkwilliams
1 Replies

5. Shell Programming and Scripting

Problem with variable ECHO $((SED...

Hi, I'm new here so I want to say hello to everyone first! I searched google and this forum for a similar problem, but wasn't successful #! /bin/bash I'm trying to output (echo) n lines of a text file to the screen (later into another file). But I have problem with the sed command, it won't... (1 Reply)
Discussion started by: studiologe
1 Replies

6. Shell Programming and Scripting

cannot pass a echo output to a variable in bash

Hi, I have a problem with passing a echo output into a variable in bash file='1990.tar' NAME='echo $file | cut -d '.' -f1'; echo $NAME the result is echo $file | cut -d . -f1 however with this one,#!/bin/bash file='1990.tar' echo $file | cut -d '.' -f1 the result is what I... (2 Replies)
Discussion started by: 1988PF
2 Replies

7. Shell Programming and Scripting

Sending Sed/Echo output to Variable

I have a variable $WORDS that contains a string Then i want to use sed to break it up. echo $WORDS | sed 's// /g' I tried setting this as a variable by doing WORDS2=`echo $WORDS | sed 's// /g'` But when i do this it does not return me to the prompt properly ie. jmpprd-v1> jmpprd-v1>... (4 Replies)
Discussion started by: nitrobass24
4 Replies

8. Shell Programming and Scripting

Echo awk output from its variable

Stumped with the formatting of the awk output when used with variables, e.g.: awk -F, 'BEGIN {OFS=","} print {$2,$3,$4}' $infile1 produces the desired output (with rows), but when echoing the variable below, the output is one continuous line var1=$(awk -F, 'BEGIN {OFS=","} print... (4 Replies)
Discussion started by: ux4me
4 Replies

9. UNIX for Dummies Questions & Answers

Passing value of a variable in sed

Hi, I want to pass value of a variable track_line which is the line number to sed. Sed should print the lines starting from track_line till the last line of the file. I tried the below command but it is not working. sed -n '${track_line},$p' latest_log_file I tried using the below too but... (1 Reply)
Discussion started by: nitinupadhyaya8
1 Replies

10. UNIX for Advanced & Expert Users

Passing variable as input & storing output in other variable

I have a below syntax its working fine... var12=$(ps -ef | grep apache | awk '{print $2,$4}') Im getting expected output as below: printf "%b\n" "${VAR12}" dell 123 dell 456 dell 457 Now I wrote a while loop.. the output of VAR12 should be passed as input parameters to while loop and results... (5 Replies)
Discussion started by: sam@sam
5 Replies
EVAL(3) 								 1								   EVAL(3)

eval - Evaluate a string as PHP code

SYNOPSIS
mixed eval (string $code) DESCRIPTION
Evaluates the given $code as PHP. Caution The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand. PARAMETERS
o $code - Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g. 'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error, whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe- cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible after it terminates. RETURN VALUES
eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to catch a parse error in eval(3) using set_error_handler(3). EXAMPLES
Example #1 eval(3) example - simple text merge <?php $string = 'cup'; $name = 'coffee'; $str = 'This is a $string with my $name in it.'; echo $str. " "; eval("$str = "$str";"); echo $str. " "; ?> The above example will output: This is a $string with my $name in it. This is a cup with my coffee in it. NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. Tip As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of this function, and save it in a string (for example). Note In case of a fatal error in the evaluated code, the whole script exits. SEE ALSO
call_user_func(3). PHP Documentation Group EVAL(3)
All times are GMT -4. The time now is 06:17 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy