06-13-2005
Archiving Files by selecting years created.
Thank you for your quick response. I have another question on this issue though.
I am already down to the actual directory I need to archive and I checked into the find command and I can find the files for a specific year, but how do I move them all at one time into the appropriate year directory? My FIND help in my book "UNIX - The Complete Reference" does not say how to do this.
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
hi all i have a requirement where in i have to zip all the files with "*.bkp" after 14 days and move the zip files to Archive directory ....
i am able to achieve the first functionality but not able to achive the second one ...here is my code
find ${LOG_DIR} -name "*.bkp" -mtime +14 | xargs -i... (1 Reply)
Discussion started by: nvuradi
1 Replies
2. Shell Programming and Scripting
Hi,
Suppose I have 2 files of yesterday's. And today I have received 3 files.
Before processing anything I want to archieve the 2 files of yesterday's into a different folder.
How can this be done?
Regards,
Sunitha (1 Reply)
Discussion started by: Sunitha_edi82
1 Replies
3. Shell Programming and Scripting
hi,
I am building a script to identify those files created/modified today and with file size 0. I am able to find the files with 0 file size and created/modified in last 24 hrs as shown below but not today (current date), I tried using (touch -t time filenm) but in my version of unix at work it... (7 Replies)
Discussion started by: rushs682
7 Replies
4. Shell Programming and Scripting
My requirement is to put all the files from output directory(ATT) to archive directory(archive\) creating a new
folder with datetimestamp(20100212_120014) every time it runs.
where ${IMF_TARGET_DIR} is my base directory.
${IMF_ARCHIVE_DIR} is my Archive directory... (1 Reply)
Discussion started by: vsmeruga
1 Replies
5. UNIX for Dummies Questions & Answers
Hello - I have a folder that contains files from 2003 till 2010. I am trying to figure out a command that would seperate each years file and show me a count?
Even if i can find a command that would give me year by year count, thats good enough too.
Thanks (8 Replies)
Discussion started by: DallasT
8 Replies
6. Shell Programming and Scripting
Hi,
In our current process we are reading the file, (which is placed by external vendor)from one particular folder and processing those files
through ETL(informatica). We are reading these file as " ls -ltr *.txt"
Once the process is finish these files are moved to archived script by "mv"... (1 Reply)
Discussion started by: Amey Joshi
1 Replies
7. UNIX for Dummies Questions & Answers
HI ,
I have a file abc.txt, which has some .csv files listed.
example.
abc.txt
1.csv
2.csv
3.csv
4.csv
5.csv
I want to move all the files listed in abc.txt to a archive directory,and zip the moved files.
Can anyone help me with the script.
Thanks,sai (1 Reply)
Discussion started by: saii
1 Replies
8. Shell Programming and Scripting
Hello Group,
I would request your help to build a shell script in order to find files older than 90 days then create the same directory structure under the second disk (/archive directory) and move the file preserving the same timestamps (ownership, etc).
Also keep the log of files moved... (4 Replies)
Discussion started by: csierra
4 Replies
9. Shell Programming and Scripting
hi,
Am trying to acrhive a bunch of files on some ftp site and somehow managed to come out with the below logic.
I'm getting "syntax error: unexpected end of file" error. Interestingly this below snipeet works fine if run for the first time but the subsequent runs fail!
Anybody has any idea... (3 Replies)
Discussion started by: Amee5
3 Replies
10. Shell Programming and Scripting
Hi,
I want to display the file names and the record count for the files in the 2nd column for the files created today.
i have written the below command which is listing the file names. but while piping the above command to the wc -l command
its not working for me.
ls -l... (5 Replies)
Discussion started by: Showdown
5 Replies
CAL(1) User Commands CAL(1)
NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS
-1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)