HOw can I use any variable in sed command.
For example I am using 'sed -e 's/?/$ORACLE_HOME/g' $file_name
Here it replaces ? with $ORACLE_HOME. Instead of it I need actual value of $ORACLE_HOME. How can I do that?
Please advice.
Thanks in advance.
Malay (13 Replies)
Hi,
My shell script searches a VALUE in a file, copies it to a variable and updates a line in another file with this new VALUE (replacing the old)
The value has a pattern-
VALUE=`$$MyDate=11-11-2008 09.09.56.123456`
(yes the $ - . = and space are all part of the string)
I am having... (6 Replies)
Hello,
i have another sed question.. I'm trying to do variable substition with sed and i'm running into a problem.
my var1 is a string constructed like this:
filename1 filerev1 filepath1
my var2 is another string constructed like this:
filename2 filerev2 filepath2
when i do... (2 Replies)
i need to use a value in the Variable to print a particular line from a file using sed command.
i tried the below one but its is not working
sed -n ' "$var"p ' abc.txt
but its is not working please help me to sort out this. (3 Replies)
I want to instert Category:XXXXX into the 2. line
something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong:
sed "2i\\${n}Category:$cat\n"
Sample:
Titel Blahh Blahh abllk sdhsd sjdhf
Blahh Blah Blahh
Blahh
Should look like... (2 Replies)
I'm trying to make a sed substitution where the substitution pattern is an environment variable to be expanded, but the variable contains a "slash".
sed -e 's/<HOME_DIRECTORY>/'$HOME'/'This gives me the following error:
sed: -e expression #1, char 21: unknown option to `s'Obviously this is... (2 Replies)
Hi Friends
in sed whether we can use variable.like the following expression.
sed -i 's/ABC/$var/g' filename
I am using Kernel 2.6.18-194.11.1.el5 RedHat linux.
I have tried sed -i 's/ABC/"$var"/g' filename, still not working.:(
Please help.
Thanks in advance
Joy (2 Replies)
Hello
i would like to interpret a variable in this command
cnt=3
sed -n '${cnt}p' file.txt
sed: 0602-403 `${cnt}`p is not a recognized function.
can you help me please ?
thanks (2 Replies)
Hi all,
Hereby wish to have your advise for below:
Main concept is
I intend to get current directory of my script file.
This script file will be copied to /etc/init.d.
A string in this copy will be replaced with current directory value.
Below is original script file:
... (6 Replies)
version=git
release=r8
echo lp-testsuite-git-r8.x86_64.rpm |sed -e "s/-$version-$release.*//g"
I want to get
lp-testsuite
what's wrong with me ? (1 Reply)
Discussion started by: yanglei_fage
1 Replies
LEARN ABOUT MOJAVE
curlopt_path_as_is
CURLOPT_PATH_AS_IS(3) curl_easy_setopt options CURLOPT_PATH_AS_IS(3)NAME
CURLOPT_PATH_AS_IS - do not handle dot dot sequences
SYNOPSIS
#include <curl/curl.h>
CURLcode curl_easy_setopt(CURL *handle, CURLOPT_PATH_AS_IS, long leaveit);
DESCRIPTION
Set the long leaveit to 1, to explicitly tell libcurl to not alter the given path before passing it on to the server.
This instructs libcurl to NOT squash sequences of "/../" or "/./" that may exist in the URL's path part and that is supposed to be removed
according to RFC 3986 section 5.2.4.
Some server implementations are known to (erroneously) require the dot dot sequences to remain in the path and some clients want to pass
these on in order to try out server implementations.
By default libcurl will merge such sequences before using the path.
DEFAULT
0
PROTOCOLS
All
EXAMPLE
CURL *curl = curl_easy_init();
if(curl) {
curl_easy_setopt(curl, CURLOPT_URL, "http://example.com/../../etc/password");
curl_easy_setopt(curl, CURLOPT_PATH_AS_IS, 1L);
curl_easy_perform(curl);
}
AVAILABILITY
Aded in 7.42.0
RETURN VALUE
Returns CURLE_OK if the option is supported, and CURLE_UNKNOWN_OPTION if not.
SEE ALSO CURLOPT_STDERR(3), CURLOPT_DEBUGFUNCTION(3), CURLOPT_URL(3),
libcurl 7.54.0 February 14, 2016 CURLOPT_PATH_AS_IS(3)