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Full Discussion: running apache on unix
Top Forums UNIX for Dummies Questions & Answers running apache on unix Post 70196 by kkarthik on Tuesday 26th of April 2005 04:32:05 PM
Old 04-26-2005
running apache on unix

Hi,
I am running an application on apache/tomcat under unix.
It was working fine until I stopped both tomcat and apache and restarted both.
Now I am getting 404 not found error.
Is there something here that I am missing.
Any help will be appreciatd.
Thx
Karthik
 

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starting(7)						 Miscellaneous Information Manual					       starting(7)

NAME
starting - event signalling that a job is starting SYNOPSIS
starting JOB=JOB INSTANCE=INSTANCE [ENV]... DESCRIPTION
The starting event is generated by the Upstart init(8) daemon when a new instance of a job begins starting. The JOB environment variable contains the job name, and the INSTANCE environment variable contains the instance name which will be empty for single-instance jobs. init(8) will wait for all services started by this event to be running, all tasks started by this event to have finished and all jobs stopped by this event to be stopped before allowing the job to continue starting. This allows jobs to effectively insert themselves as dependencies of other jobs. The event is typically combined with the stopped(7) event by services. Job configuration files may use the export stanza to export environment variables from their own environment into the starting event. See init(5) for more details. EXAMPLE
A service that wishes to be running whenever another service would be running, started before and stopped after it, might use: start on starting apache stop on stopped apache A task that must be run before another task or service is started might use: start on starting postgresql SEE ALSO
started(7) stopping(7) stopped(7) init(5) Upstart 2009-07-09 starting(7)
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