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Top Forums Programming bss(uninitialized data) segment allocation Post 70043 by jim mcnamara on Monday 25th of April 2005 12:24:09 PM
Old 04-25-2005
If string2 were
Code:
char string2[13];

then the starting address of string1 may change, depending on your system's architecture. You cannot depend on the starting position of objects in memory.

This is because the compiler may adjust the starting byte of string1 to match the addressing scheme your system uses. Or to optimize access to the object.
 

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TR(1)							      General Commands Manual							     TR(1)

NAME
tr - translate characters SYNOPSIS
tr [ -cds ] [ string1 [ string2 ] ] DESCRIPTION
Tr copies the standard input to the standard output with substitution or deletion of selected characters. Input characters found in string1 are mapped into the corresponding characters of string2. When string2 is short it is padded to the length of string1 by duplicat- ing its last character. Any combination of the options -cds may be used: -c complements the set of characters in string1 with respect to the universe of characters whose ASCII codes are 01 through 0377 octal; -d deletes all input characters in string1; -s squeezes all strings of repeated output characters that are in string2 to single characters. In either string the notation a-b means a range of characters from a to b in increasing ASCII order. The character `' followed by 1, 2 or 3 octal digits stands for the character whose ASCII code is given by those digits. A `' followed by any other character stands for that character. The following example creates a list of all the words in `file1' one per line in `file2', where a word is taken to be a maximal string of alphabetics. The second string is quoted to protect `' from the Shell. 012 is the ASCII code for newline. tr -cs A-Za-z '12' <file1 >file2 SEE ALSO
ed(1), ascii(7), expand(1) BUGS
Won't handle ASCII NUL in string1 or string2; always deletes NUL from input. 7th Edition April 29, 1985 TR(1)
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