Hello,
I create a file touch 1201093003 fichcomp
and inside a repertory (which hava a lot of files) I want to list all files created before this file :
find *.* \! -maxdepth 1 - newer fichcomp but this command returned bash: /usr/bin/find: Argument list too long
but i make a filter all... (1 Reply)
Yes , I have to find a file in unix without using any find or where commands.Any pointers for the same would be very helpful as i am beginner in shell scritping and need a solution for the same.
Thanks in advance.
Regards
Jatin Jain (10 Replies)
I need to find whether there is a file named vijay is there or not in folder named "opt" .I tried "ls *|grep vijay" but it showed permission problem.
so i need to use find command (6 Replies)
Hello everyone,
first post here, trying to learn scripting on my own and this forum as been really helpful so far. I made few little scripts working great but I m facing some problems with RE.
I have a bunch of files in many subdirectories called *001.ext *002.ext OR simple *.ext or *01.ext... (7 Replies)
Hi all ,
I'm new to unix
I have a checked project , there exists a file called xxx.config .
now my task is to find all the files in the checked out project which references to this xxx.config file.
how do i use grep or find command . (2 Replies)
Hi Friends,
Please help me to sort out this problem, I am running this in centos o/s and whenever I run this script I am getting "find: missing argument to `-exec' " but when I run the same code in the command line I didn't find any problem. I am using perl script to run this ... (2 Replies)
I need assistance with following requirement, I am new to Unix.
I want to do the following task but stuck with file creation date(sysdate)
Following is the requirement
I need to create a script that will read the abc/xyz/klm folder and look for *.err files for that day’s date and then send an... (4 Replies)
Hello,
This is a bit complicated for me.
My scenario in MyFile:
Search string1,
When string1 is found, grep the line containing string1, go back over that line in upward direction and grep the first line containing string2.
Here is an example:
MyFile
His email address... (17 Replies)
Discussion started by: baris35
17 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)