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Top Forums Programming Confusion about TCP/IP socket programming Post 62820 by crippe on Sunday 20th of February 2005 07:23:57 AM
Old 02-20-2005
Java Confusion about TCP/IP socket programming

Hello there chaps.

First of all, i'm no TCP/IP-wiz, so forgive me if this is a stupid question.
I've been messing around with filetransfer using sockets, and there is one thing that confuses me.

This is how it's set up:

A server app listens on a port for a client connection.
When it receives a connection, it forks and reads some stuff (file length, name etc.). Then it starts reading from the socket, saving the data in a local file.

Now if i make two client-connections to this server, sending two different files, it's still able to receive both files through the same port simultaniously. How is that possible? I'm guessing it has to do with different filedescriptors, but i'd like to know in detail how the kernel keeps track of which data to send to which file descriptor. Also, is this a bad way to go about filetransfer? Should i use separate ports for data and client connection?

/Crippe
 

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bubbros-server(6)						   Games Manual 						 bubbros-server(6)

NAME
bubbros-server - the bub-n-bros server. SYNOPSIS
bubbros-server [ level-file.bin ] [options] DESCRIPTION
bubbros-server starts an http server that acts as a control panel for the server. The server listens on port 8000 by default. The url for the control panel is http://server:port/0xN where 0xN is a random hex number (acts as minimal protection). This url is printed when the server starts. You can start and view games and kill the server from this panel. The control panel also allows you to type in the address of a server to connect to, the script will then open a client to that server. The http server also servers java applet clients for those players who wish to use one. When a game is started the script opens a port for the game server. This port can then be connected to by a client. Clients autodetect servers running on the local network with UDP ping on port 8056. Connection forming The client forms a tcp connection to the server. Or, when using the metaserver, the server forms a connection to the client. If this fails, the client and server try a simultaneous SYN connect. This sometimes works if the server and client are behind firewalls. The server then tries to transmit the data over udp. If it gets no response from the client it will fall back to the existing tcp connection. OPTIONS
-b N, --begin N, --start N Start at board (level) number N. The default is 1. See also the -s option. -h, --help Display help. -i, --infinite Restart the server at the end of the game. Normally the server quits after a certain period of inactivity. This is useful when used with the -m option to make a public server that is available for a long time. -l N, --lives N Limit number of lives to N. If this option is not specified the number of lives will be infinite. -m, --metaserver Register server with the Metaserver (currently) at codespeak.net:8050. This makes your server visible to everybody, and also facil- itates joining through a fascistic firewall. --port TYPE=N Sets default listening ports. If type is LISTEN , sets the game server port to N. The game server port is chosen randomly by default. If the type is HTTP , sets the http server port to N. The http server port defaults to 8000. Another port will be chosen if none was specified and 8000 is already in use. The server also listens to UDP ping on port 8056. -s N, --step N Increase board number with N when a board is completed. Defaults to 1. see also the -b option. OUTPUT
The server outputs helpful debug information concerning the http and game servers. SEE ALSO
bubbros(6) bubbros-client(6) December 7, 2007 bubbros-server(6)
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