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Top Forums Shell Programming and Scripting Date & NUmber Validation Query Post 59271 by zazzybob on Wednesday 15th of December 2004 05:26:52 AM
Old 12-15-2004
I'd use grep
Code:
$ echo "12/31/2004" | grep '^[0-1][0-9]/[0-3][0-9]/[0-9]\{4\}$' >/dev/null 2>&1
$ echo $?
0
$ echo "some text" | grep '^[0-1][0-9]/[0-3][0-9]/[0-9]\{4\}$' >/dev/null 2>&1
$ echo $?
1

You can then check $? and act accordingly.

You can extend this example to simple numerical verification...
Code:
$ echo "193912391293" | grep '^[0-9]*$'

You get the idea....

Cheers
ZB

Last edited by zazzybob; 12-15-2004 at 10:48 AM..
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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