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Top Forums UNIX for Dummies Questions & Answers could someone explain this code Post 51757 by google on Sunday 30th of May 2004 07:55:28 AM
Old 05-30-2004
'if echo $* | grep -q' $i '|| [ $# = 0 ]

This is a test of command line arguments. "echo $*" displays all of the command line arguments passed into the shell and pipes it to grep. The -q flag puts grep in quiet mode, returning exit status of 0 if grep found a matching line. In the line above, grep is searching for the value contained in the variable $i. The last bit is the second part of the test which is a test of the total number of command line arguments, which is simply asking "If the number of arguments equals 0". Putting it all together, it reads something like this: "If $i matches a command line parameter or if there are no command line parameters passed in" then "do something" (you didnt post this portion)
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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