I need a quick way to strip the last node of a directory path, given a directory path as input. The code above falls short in that the output does not include the "/" in the path. I need a way to append the "/" between each node. I have tried to do the following:
r = /
w = w r
I have the following error:
ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }'
Syntax Error The source line is 1.
The error context is
BEGIN >>> NR <<< > 1 { print $2, $9 }
awk: 0602-500 Quitting The source line is 1.
What I want to do is ls a directory, skip the first... (3 Replies)
Hello,
I have the following command that does 2 searches.
awk '{if ($0 ~ /STRING1/) {c++} }{if ( c == 2 ) {sub(/STRING1/,"NEWSTRING") } } { print }' FILE
How do I search up after the first search?
thanks (4 Replies)
i have a little awk script that I use looks this:
awk '{if (FNR==1){print FILENAME; print $0}else print $0}' file1...file2....fi... > bundled.
i have completely forgotten how to unbundle this. I have tried several different approaches and still can not remember how to unbundle the file bundled.... (2 Replies)
I am trying to read through a file, gather the states in that file and change it from an abbreviation to the ful text.
Can anyone provide some assistance.
Thanks!! (4 Replies)
How I can rid of the following presentation du -sk /u*/oradata/TEST/*.dbf |awk '{print total+=$1} 1.28003e+06
4.35109e+06
4.36134e+06
4.4535e+06
5.47752e+06
5.48777e+06
7.52554e+06
7.73036e+06
9.06158e+06
:confused: thank you (3 Replies)
Can anyone help with this this one liner:
nawk -v RS='' '$1=$1' InputFile
What I have in the file:
0.0013985457223116
-0.0002338180925628
0.0
0.0003709430584958
-0.0005763523138347
0.0
And the output I want:
0.0013985457223116 -0.0002338180925628 0.0
0.0003709430584958... (1 Reply)
I have a script problem that I am not able to solve due my very limited understanding of unix/awk.
This is the contents of test.sh
awk '{print $1}'
From the prompt if I enter:
./test.sh Hello World
I would expect to see "Hello" but all I get is a blank line. Only then if I enter "Hello... (2 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
im using ls -l | xargs | awk '{what ever files here}'
im trying to get something that looks like this... (7 Replies)
Hi Experts,
I am trying to get system output to capture inside awk , but not working:
Please advise if this is possible :
I am trying something like this but not working, the output is coming wrong:
echo "" | awk '{d=system ("date") ; print "Current date is:" , d }'
Thanks, (5 Replies)
Discussion started by: rveri
5 Replies
LEARN ABOUT MOJAVE
english
English(3pm) Perl Programmers Reference Guide English(3pm)NAME
English - use nice English (or awk) names for ugly punctuation variables
SYNOPSIS
use English;
use English qw( -no_match_vars ) ; # Avoids regex performance penalty
# in perl 5.16 and earlier
...
if ($ERRNO =~ /denied/) { ... }
DESCRIPTION
This module provides aliases for the built-in variables whose names no one seems to like to read. Variables with side-effects which get
triggered just by accessing them (like $0) will still be affected.
For those variables that have an awk version, both long and short English alternatives are provided. For example, the $/ variable can be
referred to either $RS or $INPUT_RECORD_SEPARATOR if you are using the English module.
See perlvar for a complete list of these.
PERFORMANCE
NOTE: This was fixed in perl 5.20. Mentioning these three variables no longer makes a speed difference. This section still applies if
your code is to run on perl 5.18 or earlier.
This module can provoke sizeable inefficiencies for regular expressions, due to unfortunate implementation details. If performance matters
in your application and you don't need $PREMATCH, $MATCH, or $POSTMATCH, try doing
use English qw( -no_match_vars ) ;
. It is especially important to do this in modules to avoid penalizing all applications which use them.
perl v5.18.2 2014-01-06 English(3pm)