I'm going to give it a try tomorrow when I can dedicate more time to it. Thank you so much!
Updated:
With:
The response was 1237.
Your English to Russian file seems to work fine. Whenever I've tried to use an English for French file, there was nothing inside of mysub.trans. mysub.text would look like this:
Note the space before the text and the absence of brackets. The mysub.srt file was a UTF-8, like yours.
I've attached the files I used to this post. And I'll continue to keep testing as you update it.
What is the correct format for a single command that would combine portions of 2 different lines in the command history? I'm using a C shell. Here's a simplified command history to clarify:
4 rm file1
5 ls -ld file2 file3 file4
6 cat file 5
With the above history, what would be the... (5 Replies)
I would like to change the lines:
originalline1
originalline2
to:
originalline1new
originalline1newline
originalline2new
originalline2newline
To do this, id like to combine the commands:
sed 's/^/&new/g' file > newfile1
and
sed '/^/ a\\
newline\\
\\ (2 Replies)
Hello all,
I am trying to list and count all the files of a particular type in any given directory. I can use the commands separately but when I combine them they do not give an output.
The command for counting the files is ls -1 | wc -l and for listing all the file of particular type say... (2 Replies)
Is there anyway to achieve "find /home -name "*.bashrc" 2>/dev/null" and "PS1="\n>"" in the same command? I just wanna add a line to the previous command to change the PS1 variable to ">". (1 Reply)
Hi Guys,
I am looking to optimze these 5 SSH lines to a single SSH to get my machine to not hang! lol!
cat hosts.lst | xargs -n1 -t -i echo 'home/util/timeout 6 0 ssh -q {} top -b > util/{}.top &' >> r_query_info
cat hosts.lst | xargs -n1 -t -i echo 'home/util/timeout 6 0 ssh -q {} uname -r... (5 Replies)
hey can anyone tell me how can i combine these two commands so that it is executed only once, but gives me both the results.
IDLE=`sar 30 6 | grep Average | awk '{print $1 $5}' `
sar 30 120 | awk '{print $1" "$5}' >> mailx -m -s "$MSG" xyz@abc.com. (5 Replies)
Hi,
I have a directory with some XML files in it. I can use wildcards to get the list of XMLs I want
say I have following XMLs in same dir
Employee1.xml
Employee2.xml
Employee3.xml
and
Salary1.xml
Salary2.xml
Salary3.xml
apart from other .txt .dat files etc
I want to write a unix... (7 Replies)
I have a directory of 3000 files without extensions (Solaris 5.10).
I would like to iterate the file names through the 'file' command and output their mime types (most are pdf or jpg, but a very few might be psd or swf which show simply as 'data')
So, I would like the output of the 'ls'... (2 Replies)
Hello all,
I need to send an attachment and text in the body, both in the same Email.
Below are two cammand that send the required data in separate Emails. I need to combine them so that I get just 1 Email containing the attachment & text in the body.
uuencode ${filename} "${file_}" |... (6 Replies)
Discussion started by: Junaid Subhani
6 Replies
LEARN ABOUT DEBIAN
xcalpr
XCALPR(1) General Commands Manual XCALPR(1)NAME
xcalpr - print xcal calendar entries
SYNTAX
xcalpr [ -c ][ -x ][ -f file ][ -d dir ][ -u user ][ date-spec ]
DESCRIPTION
Xcalpr prints the contents of the xcal files. It is intended to be used in situations when you have no access to an X screen. It can also
be used to generate entries for the standard UNIX calendar program.
With no arguments, it prints any entries that exist for the next seven days. The program also reads the contents of the seven daily files
and prints them at the appropriate point in the output stream. Each line in the output is preceded by the day of the week, the day of the
month, the month and the year.
Xcalpr can be given a date specification to select months and years. If the date spec consists of just a year number, then all the data
for that year is printed. For example:
xcalpr 1994
will print all the data for 1994. Several years can be specified.
If you give the name of a month, then the data for that month in the current year will be printed. If the month is in the past, then the
data for that month next year will be printed. For example, if
xcalpr oct jan
is typed in August, xcalpr will print October in the current year and January next year.
You can select a particular year by adding the number after any months that you need printing:
xcalpr oct nov 1994
will print October and November in 1994.
There are a couple of special `month' names. The name rest will print the data for the rest of the month, starting tomorrow. The rest
argument is not recognised if you give a year as a parameter. If tomorrow happens to be the first day of the next month, then all the data
for next month will be printed. The name next prints all the data for next month.
OPTIONS
The -c option causes xcalpr to output lines suitable for input to the standard UNIX calendar program.
The -d switch is followed by a directory name and specifies an alterative location for your Calendar directory. Your home directory is
prepended if the name doesn't start with a slash or a dot.
The -f option is followed by a file name and xcalpr will write it's output to that file, rather than standard output.
The -u option is followed by a user name and dumps their calendar files rather than yours.
The -x option makes xcalev operate with Calendar files that are compatible with the xcalendar program.
FILES
$HOME/Calendar/*
xc<dd><Mon><Year> A data file is day, Month in three letter format and the year.
xy<Year> A year directory.
xw<Day> A data file for the weekly code, one per day.
SEE ALSO xcal(1), xcalev(1), xcal_cal(1)AUTHOR
Copyright 1993 by Peter Collinson, Hillside Systems All rights reserved.
This product includes software developed by the University of California, Berkeley and its contributors.
X Version 11 R5 October 1993 XCALPR(1)