Hi guys
I have a shell script that executes sql statemets and sends the output to a file.the script takes in parameters executes sql and sends the result to an output file.
#!/bin/sh
echo " $2 $3 $4 $5 $6 $7
isql -w400 -U$2 -S$5 -P$3 << xxx
use $4
go
print"**Changes to the table... (0 Replies)
Hello,
I have this awk script that I want to execute by passing parameters through a shell script.
I'm a little confused. This awk script removes duplicates from an input file.
Ok, so I have a .sh file called rem_dups.sh
#!/usr/bin/sh... (4 Replies)
hi everyone
i am trying to do this
bash> cat abc.sh
deepak()
{
echo Deepak
}
deepak
bash>./abc.sh
Deepak
so it is giving me write simply i created a func and it worked
now i modified it like this way
bash> cat abc.sh (2 Replies)
This is the final first release of the dynamic menu generator for pekwm (WM).
#!/bin/bash
function param_val {
awk "/^${1}=/{gsub(/^${1}="'/,""); print; exit}' $2
}
echo "Dynamic {"
for CF in `ls -c1 /usr/share/applications/*.desktop`
do
name=$(param_val Name $CF)
... (3 Replies)
I am getting the following error while passing parameter to a shell script called within awk script. Any idea what's causing this issue and how to ix it ? Thanks
sh: -c: line 0: syntax error near unexpected token `newline'
sh: -c: line 0: `./billdatecalc.sh ... (10 Replies)
Discussion started by: Sudhakar333
10 Replies
7. Post Here to Contact Site Administrators and Moderators
Variable I have in my shell script
diff=$1$2.diff
id=$2
new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new
I could see value of $id is not passing to the awk... (0 Replies)
I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist.
diff=$1$2.diff
id=$2 new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff |... (1 Reply)
Hi
I have a text file (Input.txt) with two column entries separated by tab as given below:
aaa str1
bbb str2
cccccc str3
dddd str4
eee str3
ssss str2
sdf str3
hhh str1
fff str2
ccc str3
.....
.....
..... (1 Reply)
I'm trying to create a shell script that takes a awk script that I wrote and a filename as an argument. I was able to get that done but I'm having trouble figuring out how to keep the header of the output at the top but sort the rest of the rows alphabetically. This is what I have now but it is... (1 Reply)
Discussion started by: Eric7giants
1 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)