Passing shell script parameter value to awk command in side the script


 
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# 1  
Old 01-28-2014
Passing shell script parameter value to awk command in side the script

I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist.

Code:
diff=$1$2.diff  
id=$2 new=new_$diff   
echo "My id is $1"  
echo "I want to  sync for user account $id"   
##awk command I am using is as below   
cat  $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new

I also tried below options but no success, please suggest.

Code:
awk -F'~' -v search=$id '$2 == "search" {print $0} file'  nayaka2almadm1.diff > $new cat 
$diff | awk -v "search=$id" -F'~'  '$2 == "search" {print $0}' > $new 
cat $diff | awk -F'~' -v  search="$id" '$2 ~ "^\"search {print $0}' > $new 
awk -v  search="$id" file="$diff" | awk -F'~' '$2 == search {print $0} file'  > $new

# 2  
Old 01-28-2014
Something like this?
Code:
diff=${1}${2}.diff  
id=$2
new=new_${diff}
awk -F'~' -v fId="$id" '$2 == fId' $diff > $new

 
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