SHELL: UNIX : Ls regular expression not working when used with variables
If i do below command in unix prompt which static values (ie 27..97), it is working fine and gives desired output
But if i want to include variables or pass arguments to regular expression then its giving me error "ls: cannot access /home/work/batch/somefilename_{27..96}.*: No such file or directory". But thats not true bec file is present but somehow with variables regex is not working.
Can someone please advise here why the regular expression is not working when using ls and {..} with variables?
Note: I am trying to store all the directory names in an array whose directory name is between two integer number
for eg there are 1-100 dir available with name file_1.some file_2.some file_3.some .. file_100.some.
If user wants to get directory from 47 till 97, then i want to read that value, store them and pass it in above ls command.
If you have any other alternative that will also help.
Hi,
Actually i have written one test.sh (shell program) in bash.
Here i have a variables $a which stored the value package1.
Now I want to write a regular expression inside the if command that "if $a variable contains letter p in the begining of the value package1 then it is coming true.... (5 Replies)
Hi,
I have to match a certain pattern of string in my shell script:
6.0.4.11.9
7.5.1.7.1
First Number can be 6 or 7
Second number can be 0 or 5
Rest all numbers can be between 1-99
I am using following egrep:
egrep ^\.\.\.\.\$ filename
But why is the above regular... (1 Reply)
I have the following code:
ls -al /bin | tr -s ' ' | grep 'x'
ls -al: Lists all the files in a given director such as /bin
tr -s ' ': removes additional spaces between characters so that there is only one space
grep 'x': match all "x" characters that are followed by a whitespace.
I was... (3 Replies)
hi,
I have written a script to search MAC address in a given directory.
MAC address would be in format XX.XX.XX.XX.
The digits contain hexadecimal numbers.
For this i have used grep as follows.
grep -rn '^\{1,2\}\.\{1,2\}\.\{1,2\}\.\{1,2\}\$' *
This is not working as required.... (17 Replies)
Hi All,
I am facing some problems with regular expression with sed.
I have a .txt file with the contents as below:
This is a dummy file
# File created to test execution of regular expression.
Hope it works out.
As in the above contents there is a blank line which does not... (4 Replies)
Hi all,
How am I read a file, find the match regular expression and overwrite to the same files.
open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat";
open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat";
while (<DESTINATION_FILE>)
{
# print... (1 Reply)
Hello ,
Could anyone help me to define the string in regular expression way .
Below is my string
\rtf1\ansi\deff0{\fonttbl{\f0\fswiss Helv;}{\f1\fnil MS Sans Serif;}}
{\colortbl ;\red0\green0\blue0;}
\viewkind4\uc1\pard\cf1\lang1033\f0\fs16
The string will always start as \rtf1 and... (6 Replies)
How can I define a regular expression of a string which can start with Capital alphabet or integer (A-Z) or (0-9) and can be of any number of characters
I have tried * but its not working
could anyone please suggest? (2 Replies)
Hello Everyone,
I have a file sam1 with the below content
SYSYSID;MANDT;/SIE/AD_Z0M_INDX;/SIE/AD_Z0M_KEY1
echo $Regex
\bSYSYSID\b|\bMANDT\b|\b/SIE/AD_Z0M_INDX\b|\b/SIE/AD_Z0M_KEY1\b
cat sam1 | grep -Eo $Regex
I expect the result as
SYSYSID
MANDT
/SIE/AD_Z0M_INDX
/SIE/AD_Z0M_KEY1... (4 Replies)
Discussion started by: sam99
4 Replies
LEARN ABOUT V7
expr
EXPR(1) General Commands Manual EXPR(1)NAME
expr - evaluate arguments as an expression
SYNOPSIS
expr arg ...
DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr
yields the first expr if it is neither null nor `0', otherwise yields the second expr.
expr & expr
yields the first expr if neither expr is null or `0', otherwise yields `0'.
expr relop expr
where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if
both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
multiplication, division, or remainder of the arguments.
expr : expr
The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is
the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the
matching operator yields the number of characters matched (`0' on failure).
( expr )
parentheses for grouping.
Examples:
To add 1 to the Shell variable a:
a=`expr $a + 1`
To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/':
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
SEE ALSO ed(1), sh(1), test(1)DIAGNOSTICS
Expr returns the following exit codes:
0 if the expression is neither null nor `0',
1 if the expression is null or `0',
2 for invalid expressions.
EXPR(1)