I wrote this small bash script, i want to compare second column from file1 with file2 if a pattern matches. Files are small and I am sure that pattern occurs only once. I think this can be rewritten into a awk one liner. Appreciate if someone could give me idea. Whole NR FNR confuse me
Hi all this is simple but bad day for me nothing work out ..
Problem is that I wan to check the argument passed to my script and accordignly exit or setup ENV variable
I have a script name src_cpcp_preproc.sh
i want to pass 2 argumet from command line argumet and check it in the script... (13 Replies)
Hi group,
I want to replace the occurance of a particular text in a paragraph.I tried with Sed,but Sed only displays the result on the screen.How can i update the changes in the original file???
The solution should be a one liner using awk and sed.
Thanks in advance. (5 Replies)
Hello all, I have a Bash command I'm using on one system that replaces text in filenames, I'ts not working on another system that uses the Csh shell. Can anyone tell me what I need to do
when i run
for f in *;do mv $f ${f/text1/text2};done
on the CSH shell i get ""Missing }."" (7 Replies)
There's a replacement in bash for getchar or get functions of C and C++?Those functions read the next char avaliable in the input stream.
I've tried something like:
OLD_STTY=`stty -g`
stty cbreak -echo
look=`dd if=/dev/tty bs=1 count=1 2>/dev/null`
stty $OLD_STTY
But it is not working... (3 Replies)
Hello
I have a bash script where I need to do a substring replacement like this:
variable2=${variable1/foo/bar}
However, I only want "foo" replaced if it is at the end of the line.
However, this does not work:
variable2=${variable1/foo$/bar}
as you can see I'm using the $ regex for... (2 Replies)
Thanks for giving your time and effort to answer questions and helping newbies like me understand awk.
I have a huge file, millions of lines, so perl takes quite a bit of time, I'd like to convert these perl one liners to awk.
Basically I'd like all lines with ISA sandwiched between... (9 Replies)
Hello experts,
I'm stuck with this script for three days now. Here's what i need.
I need to split a large delimited (,) file into 2 files based on the value present in the last field.
Samp: Something.csv
bca,adc,asdf,123,12C
bca,adc,asdf,123,13C
def,adc,asdf,123,12A
I need this split... (6 Replies)
I have some time series data that I need to resample or downsample at some specific time intervals. The firs column is time in decimal hours. I am tryiong to resample this data every 3 minutse. So I need a data value ever 0.05. Here is the example data and as you can see, there time slot for 0.1500... (3 Replies)
Hi
I want to replace time stamp in the following line
PROCNAME.Merge.exchMon.CODE.T_QSTART 08:45 read
assuming the new time stamp is 09:45 ; the line is getting replaced as below
:45 read
I'm trying to use the perl one liner in bash script
perl -pi... (4 Replies)
Discussion started by: charlie87
4 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)