How to delete everything present on left (or right) of a substring?
Hello,
I have list of lines from which i am trying to pick a sub string and want to put that into a csv file, the sub string i want to extract is at the middle of the line, i was wondering how can i delete everything that is present left/right of a sub string. I have tried sed, cut and awk, but i couldn't get desired results.
Below are few lines, from which i am trying to pick PXCNUMBER_1 and append them to a csv file.
using awk and cut i got this result, due to some inconsistency in the lines i failed to pick the PXCNUMBERS_1, precisely as you could see there is MSGS_ in the last line before PXCNUMBERS_1 .
I know i could use sed to replace MSGS in the last line to empty, but there are more lines than i have showed above, and i was also curious to know if there is any command to cut everything left/right of a sub string. any pointers would be great help
I have a script which loop through a directory then report any file matches the given pattern,
say, the pattern is "a2006", this file would be returned
a20061101.txt
I would like to know how can I get the remaining of the filename, so
a20061101txt - a2006 = 1101.txt
Can anybody help? Thank... (2 Replies)
hi
i have a file which is like this :
aab ghj
ghj lsklk
lklkl;
ashjd
kjs
alskj
How do i remove the spaces from the beginning of a line so that all lines are indented to the left? (1 Reply)
Hi all,
A very strange problem I have this morning with my Solaris 8.
I have a FS full, I deleted some files but the system doesn't seems to reallocate the free space (I'm using Veritas):
df -k :
/dev/vx/dsk/dlds02vg/dlds02oralv 4194304 4194304 0 100% /dlds02/lds/oracle
... (4 Replies)
HI,
if a String is present in file1.txt, i want to delete that String from file2.txt.
How can i do this??
I am sure that the file1.txt is a subset of file2.txt. (2 Replies)
I am passing input string,length, and the pad character.
input string=123
Pad char=#
Length=6
then the output should be:
###123
How we can do this?
Thanks (5 Replies)
I have two files
File1
====
1|2000-00-00|2010-02-02||
2| 00:00:00|2012-02-24||
3|2000-00-00|2011-02-02||
File2
====
2000-00-00
00:00:00
I want the delete the patterns which are found in file 2 from file 1,
Expected output:
File1
==== (5 Replies)
Need unix commands to delete records from one file if the same record present in another file...
just like join ... if the record present in both files.. delete from first file or delete the particular record and write the unmatched records to new file..
tried with grep and while... (6 Replies)
Hi guys,
I need to use awk to join 2 files
file_1
A 001
B 002
C 003
file_2
A XX1
B XX2
output desired
A 001 XX1
B 002 missing
C 003 XX2
thank you! (2 Replies)
here is what i want to achieve.. i have a file with below contents
cat fileName
blah blah blah
.
.DROP this
REJECT that
.
--sport 7800 -j REJECT --reject-with icmp-port-unreachable
--dport 7800 -j REJECT --reject-with icmp-port-unreachable
.
.
.
more blah blah blah
--dport 3306... (14 Replies)
I know that it is possible to login into the HMC console and view all the specs like, how much CPU/RAM every LPAR has.
But how can I check how much the whole P7 has in total and how much is left to creat a new LPAR:wall: (5 Replies)
Discussion started by: DiViN3
5 Replies
LEARN ABOUT OPENSOLARIS
regex
regex(1F) FMLI Commands regex(1F)NAME
regex - match patterns against a string
SYNOPSIS
regex [-e] [-v "string"] [pattern template] ...
pattern [template]
DESCRIPTION
The regex command takes a string from the standard input, and a list of pattern / template pairs, and runs regex() to compare the string
against each pattern until there is a match. When a match occurs, regex writes the corresponding template to the standard output and
returns TRUE. The last (or only) pattern does not need a template. If that is the pattern that matches the string, the function simply
returns TRUE. If no match is found, regex returns FALSE.
The argument pattern is a regular expression of the form described in regex(). In most cases, pattern should be enclosed in single quotes
to turn off special meanings of characters. Note that only the final pattern in the list may lack a template.
The argument template may contain the strings $m0 through $m9, which will be expanded to the part of pattern enclosed in ( ... )$0 through
( ... )$9 constructs (see examples below). Note that if you use this feature, you must be sure to enclose template in single quotes so that
FMLI does not expand $m0 through $m9 at parse time. This feature gives regex much of the power of cut(1), paste(1), and grep(1), and some
of the capabilities of sed(1). If there is no template, the default is $m0$m1$m2$m3$m4$m5$m6$m7$m8$m9.
OPTIONS
The following options are supported:
-e Evaluates the corresponding template and writes the result to the standard output.
-v "string" Uses string instead of the standard input to match against patterns.
EXAMPLES
Example 1 Cutting letters out of a string
To cut the 4th through 8th letters out of a string (this example will output strin and return TRUE):
`regex -v "my string is nice" '^.{3}(.{5})$0' '$m0'`
Example 2 Validating input in a form
In a form, to validate input to field 5 as an integer:
valid=`regex -v "$F5" '^[0-9]+$'`
Example 3 Translating an environment variable in a form
In a form, to translate an environment variable which contains one of the numbers 1, 2, 3, 4, 5 to the letters a, b, c, d, e:
value=`regex -v "$VAR1" 1 a 2 b 3 c 4 d 5 e '.*' 'Error'`
Note the use of the pattern '.*' to mean "anything else".
Example 4 Using backquoted expressions
In the example below, all three lines constitute a single backquoted expression. This expression, by itself, could be put in a menu defini-
tion file. Since backquoted expressions are expanded as they are parsed, and output from a backquoted expression (the cat command, in this
example) becomes part of the definition file being parsed, this expression would read /etc/passwd and make a dynamic menu of all the login
ids on the system.
`cat /etc/passwd | regex '^([^:]*)$0.*$' '
name=$m0
action=`message "$m0 is a user"`'`
DIAGNOSTICS
If none of the patterns match, regex returns FALSE, otherwise TRUE.
NOTES
Patterns and templates must often be enclosed in single quotes to turn off the special meanings of characters. Especially if you use the
$m0 through $m9 variables in the template, since FMLI will expand the variables (usually to "") before regex even sees them.
Single characters in character classes (inside []) must be listed before character ranges, otherwise they will not be recognized. For exam-
ple, [a-zA-Z_/] will not find underscores (_) or slashes (/), but [_/a-zA-Z] will.
The regular expressions accepted by regcmp differ slightly from other utilities (that is, sed, grep, awk, ed, and so forth).
regex with the -e option forces subsequent commands to be ignored. In other words, if a backquoted statement appears as follows:
`regex -e ...; command1; command2`
command1 and command2 would never be executed. However, dividing the expression into two:
`regex -e ...``command1; command2`
would yield the desired result.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO awk(1), cut(1), grep(1), paste(1), sed(1), regcmp(3C), attributes(5)SunOS 5.11 12 Jul 1999 regex(1F)