Sponsored Content
Top Forums UNIX for Beginners Questions & Answers How to identify delimiter to find and replace a string with sed? Post 303040454 by RudiC on Tuesday 29th of October 2019 05:27:00 PM
Old 10-29-2019
How specific the date regex has to be? Is it OK to match 31-FEB? Any condidtions for the year, e.g. only 20xx, or 19xx as well? Does your sed handle EREs? Try
Code:
NEWDATE=01-OCT-2019
sed -r "s/[0-3][0-9]-($(locale abmon | tr 'a-z;' 'A-Z|'))-[12][09][0-9]{2}/$NEWDATE/" file
       ep.begin_date, ep.end_date, ep.facility_code,
       AND     ep.begin_date <= '01-OCT-2019'
                     ep.begin_date, ep.end_date, ep.facility_code,
       AND     ep.begin_date <= '01-OCT-2019'
                     ep.begin_date, ep.end_date, ep.facility_code,
       AND    ep.begin_date <= '01-OCT-2019'

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

How to find a certain string in a file and replace it with a value from another file using sed/awk?

Hi Everyone, I am new to this forum and new to sed/awk programming too !! I need to find particular string in file1(text file) and replace it with a value from another text file(file2) the file2 has only one line and the value to be replaced with is in the second column. file 1: (assert (=... (21 Replies)
Discussion started by: paramad
21 Replies

2. Shell Programming and Scripting

replace (sed?) a string in file with multiple lines (string) from variable

Can someone tell me how I can do this? e.g: a=$(echo -e wert trewt ertert ertert ertert erttert erterte rterter tertertert ert) How do i replace the STRING with $a? I try this: sed -i 's/STRING/'"$a"'/g' filename.ext but this don' t work (2 Replies)
Discussion started by: jforce
2 Replies

3. Shell Programming and Scripting

Help identify string using sed

I have the following output and would like to only identify strings with "vw" at the end. Here is the file contents: SELECT n.contract_num, n.descr, s.prj_level2_cf_val, r.descr, r.project_id, p.offering_id, o.n_cust_contract, u.name1, ' ', ' ', SUM (0), TO_CHAR (t.start_dt, 'YYYY-MM-DD'),... (6 Replies)
Discussion started by: bobroberts369
6 Replies

4. Shell Programming and Scripting

QUESTION1: grep only exact string. QUESTION2: find and replace only exact value with sed

QUESTION1: How do you grep only an exact string. I am using Solaris10 and do not have any GNU products installed. Contents of car.txt CAR1_KEY0 CAR1_KEY1 CAR2_KEY0 CAR2_KEY1 CAR1_KEY10 CURRENT COMMAND LINE: WHERE VARIABLE CAR_NUMBER=1 AND KEY_NUMBER=1 grep... (1 Reply)
Discussion started by: thibodc
1 Replies

5. Shell Programming and Scripting

Using sed in ksh to find and replace string

Hi All, I have a file in which contains location of various data files. I want to change locations using sed. Find and replace strings are in a separate file. Content of this file (/tmp/tt) - /dd/pp/test/test/1/ /pp/aa/test/dg1/ /dd/pp/test/test/2/ /pp/aa/test/dg2/ /dd/pp/test/test/3/... (2 Replies)
Discussion started by: pandeyra
2 Replies

6. Shell Programming and Scripting

sed or awk command to replace a string pattern with another string based on position of this string

here is what i want to achieve... consider a file contains below contents. the file size is large about 60mb cat dump.sql INSERT INTO `table1` (`id`, `action`, `date`, `descrip`, `lastModified`) VALUES (1,'Change','2011-05-05 00:00:00','Account Updated','2012-02-10... (10 Replies)
Discussion started by: vivek d r
10 Replies

7. Shell Programming and Scripting

HPUX find string in directory and filetype and replace string

Hi, Here's my dilemma. I need to replace the string Sept_2012 to Oct_2012 in all *config.py files within the current directory and below directories Is this possible? Also I am trying to find all instances of the string Sept_2012 within files in the current directory and below I have... (13 Replies)
Discussion started by: pure_jax
13 Replies

8. Shell Programming and Scripting

Help with Passing the Output of grep to sed command - to find and replace a string in a file.

I have a file example.txt as follows :SomeTextGoesHere $$TODAY_DT=20140818 $$TODAY_DT=20140818 $$TODAY_DT=20140818I need to automatically update the date (20140818) in the above file, by getting the new date as argument, using a shell script. (It would even be better if I could pass... (5 Replies)
Discussion started by: SriRamKrish
5 Replies

9. Shell Programming and Scripting

Sed: find and replace backwards, until string

Some help please: Need to find string ||(everything in front of it)B0300|| and replace it with ||0|| globally In: 16112121||||0||0||0||0||0||52||52||0||0||0||0||1507200053342B0300||1507200053342B0300||0||0||0||0700 Out: 16112121||||0||0||0||0||0||52||52||0||0||0||0||0||0||0||0||0||0700 ... (4 Replies)
Discussion started by: drbiloukos
4 Replies

10. UNIX for Beginners Questions & Answers

sed find replace after HOST string

Hi Everyone, I have a xml file, where i need to find this HOST=dbhost.domain.com and then replace only dbhost.domain.com with db.one.in so finally it should like this HOST=db.one.in i tried this but its not working. sed -i "s/^HOST=*com$/HOST=db.one.in/g" repository.xml ^... (4 Replies)
Discussion started by: shajay12
4 Replies
regex(1F)							   FMLI Commands							 regex(1F)

NAME
regex - match patterns against a string SYNOPSIS
regex [-e] [-v "string"] [pattern template] ... pattern [template] DESCRIPTION
The regex command takes a string from the standard input, and a list of pattern / template pairs, and runs regex() to compare the string against each pattern until there is a match. When a match occurs, regex writes the corresponding template to the standard output and returns TRUE. The last (or only) pattern does not need a template. If that is the pattern that matches the string, the function simply returns TRUE. If no match is found, regex returns FALSE. The argument pattern is a regular expression of the form described in regex(). In most cases, pattern should be enclosed in single quotes to turn off special meanings of characters. Note that only the final pattern in the list may lack a template. The argument template may contain the strings $m0 through $m9, which will be expanded to the part of pattern enclosed in ( ... )$0 through ( ... )$9 constructs (see examples below). Note that if you use this feature, you must be sure to enclose template in single quotes so that FMLI does not expand $m0 through $m9 at parse time. This feature gives regex much of the power of cut(1), paste(1), and grep(1), and some of the capabilities of sed(1). If there is no template, the default is $m0$m1$m2$m3$m4$m5$m6$m7$m8$m9. OPTIONS
The following options are supported: -e Evaluates the corresponding template and writes the result to the standard output. -v "string" Uses string instead of the standard input to match against patterns. EXAMPLES
Example 1 Cutting letters out of a string To cut the 4th through 8th letters out of a string (this example will output strin and return TRUE): `regex -v "my string is nice" '^.{3}(.{5})$0' '$m0'` Example 2 Validating input in a form In a form, to validate input to field 5 as an integer: valid=`regex -v "$F5" '^[0-9]+$'` Example 3 Translating an environment variable in a form In a form, to translate an environment variable which contains one of the numbers 1, 2, 3, 4, 5 to the letters a, b, c, d, e: value=`regex -v "$VAR1" 1 a 2 b 3 c 4 d 5 e '.*' 'Error'` Note the use of the pattern '.*' to mean "anything else". Example 4 Using backquoted expressions In the example below, all three lines constitute a single backquoted expression. This expression, by itself, could be put in a menu defini- tion file. Since backquoted expressions are expanded as they are parsed, and output from a backquoted expression (the cat command, in this example) becomes part of the definition file being parsed, this expression would read /etc/passwd and make a dynamic menu of all the login ids on the system. `cat /etc/passwd | regex '^([^:]*)$0.*$' ' name=$m0 action=`message "$m0 is a user"`'` DIAGNOSTICS
If none of the patterns match, regex returns FALSE, otherwise TRUE. NOTES
Patterns and templates must often be enclosed in single quotes to turn off the special meanings of characters. Especially if you use the $m0 through $m9 variables in the template, since FMLI will expand the variables (usually to "") before regex even sees them. Single characters in character classes (inside []) must be listed before character ranges, otherwise they will not be recognized. For exam- ple, [a-zA-Z_/] will not find underscores (_) or slashes (/), but [_/a-zA-Z] will. The regular expressions accepted by regcmp differ slightly from other utilities (that is, sed, grep, awk, ed, and so forth). regex with the -e option forces subsequent commands to be ignored. In other words, if a backquoted statement appears as follows: `regex -e ...; command1; command2` command1 and command2 would never be executed. However, dividing the expression into two: `regex -e ...``command1; command2` would yield the desired result. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWcsu | +-----------------------------+-----------------------------+ SEE ALSO
awk(1), cut(1), grep(1), paste(1), sed(1), regcmp(3C), attributes(5) SunOS 5.11 12 Jul 1999 regex(1F)
All times are GMT -4. The time now is 12:47 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy