Hai I just want to find a file *.txt in particular direcotry and display the file name puls the content. Do someone know hot to do this, thanks.
I try :
find test/ -name '*.txt' | xargs cat
but It does'nt print out the file name, i want something below print out in my screen :
test/1.txt... (4 Replies)
Hello,
So I sorted my file as I was supposed to:
sort -n -r -k 2 -k 1 file1 | uniq > file2
and when I wrote
> cat file2
in the command line, I got what I was expecting, but in the script itself
...
sort -n -r -k 2 -k 1 averages | uniq > temp
cat file2
It wrote a whole... (21 Replies)
Hi,
I am having trouble getting a combination of commands to work.
I need to traverse through all sub-directories of a certain directory and 'cat' the contents of a particular file in the sub-directories.
The commands on their own work but when I combine them I get no output.
The... (4 Replies)
Hi
I have to find if a pattern is present in a line.
eq
line="dasdasd hello asdasdasd"
Have to find if "hello" is present in the line or not.
Which command to be used?
Thanks (10 Replies)
Hi,
I am creating a script to do a find and replace single/multiple lines in a file with any number of lines.
I have written a logic in a script that reads a reference file say "findrep" and populates two variables $FIND and $REPLACE
print $FIND gives
Hi How r $u
Rahul()
Note:... (0 Replies)
I am trying to delete files older than 60 days from a folder:
find /myfolder/*.dat -mtime +60 -exec rm {} \;
ERROR - argument list too long: find
I can't just give the folder name, as there are some files that I don't want to delete. So i need to give with the pattern (*.dat). I can... (3 Replies)
How can I recursively find all files in a directory and print out the file and first line number of any text blocks that match the below cases?
This would seem to involve find, xargs, *grep, regex, etc.
In summary, I want to find so-called empty "try-catch blocks" that do not contain code... (0 Replies)
Guys, need help.
I have a file that contains something like this:
abc
def
ghi
jkl
I want to print the first and last line of the file and the output should be in a single line.
so, output should be like this:
abc jkl (3 Replies)
Hi all,
How can i display the middle line of a file using a single line command? (6 Replies)
Discussion started by: Lakme Pemmaiah
6 Replies
LEARN ABOUT DEBIAN
bup-join
bup-join(1) General Commands Manual bup-join(1)NAME
bup-join - concatenate files from a bup repository
SYNOPSIS
bup join [-r host:path] [refs or hashes...]
DESCRIPTION
bup join is roughly the opposite operation to bup-split(1). You can use it to retrieve the contents of a file from a local or remote bup
repository.
The supplied list of refs or hashes can be in any format accepted by git(1), including branch names, commit ids, tree ids, or blob ids.
If no refs or hashes are given on the command line, bup join reads them from stdin instead.
OPTIONS -r, --remote=host:path
Retrieves objects from the given remote repository instead of the local one. path may be blank, in which case the default remote
repository is used. The connection to the remote server is made with SSH. If you'd like to specify which port, user or private key
to use for the SSH connection, we recommend you use the ~/.ssh/config file.
EXAMPLE
# split and then rejoin a file using its tree id
TREE=$(tar -cvf - /etc | bup split -t)
bup join $TREE | tar -tf -
# make two backups, then get the second-most-recent.
# mybackup~1 is git(1) notation for the second most
# recent commit on the branch named mybackup.
tar -cvf - /etc | bup split -n mybackup
tar -cvf - /etc | bup split -n mybackup
bup join mybackup~1 | tar -tf -
SEE ALSO bup-split(1), bup-save(1), ssh_config(5)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-join(1)