Hi All,
I have a filelist which contains the "ls" output, i want to extract the filenames written in this files based on date. I know i can run loop and extract the file but i want to avoid it. also there is find command which can be used on directory i.e.
But is there any way i can use find on Filelist instead of directory and get the file name. TIA
Hi All,
I am new to shell srcipting.
Problem :
I need to write a script which copy the log files from /prod/logs directory based on todays date like (Jul 17) and place it to /home/hzjnr0 directory and then search the copied logfiles for the string "@ending successfully on Thu Jul 17". If... (2 Replies)
Hi,
I have a filelist named filestomove.txt.
It can contain any number of files that need to be moved to a subdirectory.
All the files from filelist are in the same directory as the filelist, let say it's called Folder1.
All the files need to be moved to subfolder Folder1/Subfolder1.
... (1 Reply)
Hello,
I need some sort of way to extract every date contained in a file, and count how many of those dates there are.
Here are the specifics:
The date format I'm looking for is mm/dd/yyyy
I only need to look after line 45 in the file (that's where the data begins)
The columns of... (2 Replies)
Hi,
We've a list of files that gets created on a weekly basis and it has got a date and time embedded to it. Below are the examples. I want to find out how to get the latest files get the date and time stamp out of it.
Files are
PQR123.PLL.M989898.201308012254.gpg... (1 Reply)
Hi,
My first time on this site, please excuse me if I've come to the wrong forum. I'm fairly new to Unix/Linux and hoping you can help me out.
I'm looking for a command line that will return a list of directories that are larger than 50M and older than 2 days.
I thought it may be... (6 Replies)
Hi
I am unable to find files, those are present anywhere in the same directory tree, based on the creation date. I need to find the files with their path, as I need to create them in another location and move them. I need some help with a script that may do the job.
Please help (2 Replies)
Hi All ,
I am trying to find some non empty files from a directory based on below conditions :
Files::
SIZE DATE FILE
3679 Jan 25 23:59 belk_rpo_error_po9324892_01252014.log
0 Jul 01 06:30 belk_rpo_error_po9324267_07012014.log
0 Jul 20 05:50... (7 Replies)
My unix version is IBM AIX Version 6.1
I tried google my requirement and found the below answer,
find . -newermt “2012-06-15 08:13" ! -newermt “2012-06-15 18:20"
But newer command is not working in AIX version 6.1 unix
I have given my requirement below:
Input:
atr files:
... (1 Reply)
Hi Team,
I'm new to unix and i have a requirement to copy or move files from one directory to another based on current date mentioned in the .zip file name. Note that i need to copy only the recent zip file. please help me with the code
i tried the code as:
#! /usr/bin/sh
find... (3 Replies)
Discussion started by: midhun3108
3 Replies
LEARN ABOUT ULTRIX
mu-extract
MU-EXTRACT(1) General Commands Manual MU-EXTRACT(1)NAME
mu_extract - display and save message parts (attachments), and open them with other tools.
SYNOPSIS
mu extract [options] <file> mu extract [options] <file> <pattern>
DESCRIPTION
mu extact is the mu sub-command for extracting MIME-parts (e.g., attachments) from mail messages. It works on message files, and does not
require the message to be indexed in the database.
For attachments, the file name used when saving it, is the name of the attachment in the message. If there is no such name, or when saving
non-attachment MIME-parts, a name is derived from the message-id of the message.
If you specify a pattern (a case-insensitive regular expression) as the second argument, all attachments with filenames matching that pat-
tern will be extracted. The regular expressions are Perl-compatible (as per the PCRE-library).
Without any options, mu extract simply outputs the list of leaf MIME-parts in the message. Only 'leaf' MIME-parts (including RFC822 attach-
ments) are considered, multipart/* etc. are ignored.
OPTIONS -a, --save-attachments
save all MIME-parts that look like attachments.
--save-all
save all non-multipart MIME-parts.
--parts=<parts>
only consider the following numbered parts (comma-separated list).The numbers for the parts can be seen from running mu extract
without any options but only the message file.
--target-dir=<dir>
save the parts in the target directory rather than the current working directory.
--overwrite
overwrite existing files with the same name; by default overwriting is not allowed.
--play Try to 'play' (open) the attachment with the default
application for the particular file type. On MacOS, this uses the open program, on other platforms is uses xdg-open. You can choose
a different program by setting the MU_PLAY_PROGRAM environment variable.
EXAMPLES
To display information about all the MIME-parts in a message file:
$ mu extract msgfile
To extract MIME-part 3 and 4 from this message, overwriting existing files with the same name:
$ mu extract --parts=3,4 --overwrite msgfile
To extract all files ending in '.jpg' (case-insensitive):
$ mu extract msgfile '.*.jpg'
To extract an mp3-file, and play it in the the default mp3-playing application.
$ mu extract --play msgfile 'whoopsididitagain.mp3'
BUGS
Please report bugs if you find them: http://code.google.com/p/mu0/issues/list
AUTHOR
Dirk-Jan C. Binnema <djcb@djcbsoftware.nl>
SEE ALSO mu(1)User Manuals February 2012 MU-EXTRACT(1)