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Top Forums Shell Programming and Scripting Need to split string on single quote as delimiter Post 303038152 by mohtashims on Tuesday 27th of August 2019 02:42:50 AM
Old 08-27-2019
FPATH gets the string by reading it from a file hello.txt.
Code:
input="./hello.txt"
while IFS= read -r line
do
  echo "$line"
IFS=': ' read -r ip string <<< "$line"

Below is how I tried your suggestion.

Code:
a=`echo $FPATH | tr "'" "\n" | sed "s/^ //g"`
   for i in "${a[@]}"
do
   printf '$i' >> output.txt
done

However, due to single quotes printf '$i' we get the output which is enclosed in single quotes.

If I print without single quotes i.e printf $i then the print statement fails becoz of illegal argument like "-r"
Code:
uname -a
Linux mymac 3.10.0-957.12.1.el7.x86_64 #1 SMP Wed Mar 20 11:34:37 UTC 2019 x86_64 x86_64 x86_64 GNU/Linux

 

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PRINT(3)								 1								  PRINT(3)

print - Output a string

SYNOPSIS
int print (string $arg) DESCRIPTION
Outputs $arg. print is not actually a real function (it is a language construct) so you are not required to use parentheses with its argument list. PARAMETERS
o $arg - The input data. RETURN VALUES
Returns 1, always. EXAMPLES
Example #1 print examples <?php print("Hello World"); print "print() also works without parentheses."; print "This spans multiple lines. The newlines will be output as well"; print "This spans multiple lines. The newlines will be output as well."; print "escaping characters is done "Like this"."; // You can use variables inside a print statement $foo = "foobar"; $bar = "barbaz"; print "foo is $foo"; // foo is foobar // You can also use arrays $bar = array("value" => "foo"); print "this is {$bar['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value print 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just print variables print $foo; // foobar print <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon no extra whitespace! END; ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
echo(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group PRINT(3)
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