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Full Discussion: Help - Bash Script
Top Forums UNIX for Beginners Questions & Answers Help - Bash Script Post 303035470 by Stefano on Saturday 25th of May 2019 09:51:17 AM
Old 05-25-2019
Hi Don and thank you so much for answer. I solved. The code posted is used, in that case, as a regular expression for a date in the format YYYY-MM-DD where YYYY is the current year, less the value of the variable {i}.

But now, I have one other issue very very difficult to understand (for me, naturally).

I would know what does mean this code
Code:
ls ${BACKUPDIR} | grep -v -e "$(echo -n $(listUniqueBackups) | sed "s//\\\|g")"

...
... in particular the two sections | grep -v -e "$echo -n ... and ... sed "s//\\\|g"

Thanks in advance.

PS The code is a command of linux bash script !

Last edited by Scrutinizer; 05-25-2019 at 12:17 PM.. Reason: code tags
 

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EREG(3) 								 1								   EREG(3)

ereg - Regular expression match

SYNOPSIS
int ereg (string $pattern, string $string, [array &$regs]) DESCRIPTION
Searches a $string for matches to the regular expression given in $pattern in a case-sensitive way. Warning This function has been DEPRECATED as of PHP 5.3.0. Relying on this feature is highly discouraged. PARAMETERS
o $pattern - Case sensitive regular expression. o $string - The input string. o $regs - If matches are found for parenthesized substrings of $pattern and the function is called with the third argument $regs, the matches will be stored in the elements of the array $regs. $regs[1] will contain the substring which starts at the first left parenthesis; $regs[2] will contain the substring starting at the second, and so on. $regs[0] will contain a copy of the complete string matched. RETURN VALUES
Returns the length of the matched string if a match for $pattern was found in $string, or FALSE if no matches were found or an error occurred. If the optional parameter $regs was not passed or the length of the matched string is 0, this function returns 1. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 4.1.0 | | | | | | | Up to (and including) PHP 4.1.0 $regs will be | | | filled with exactly ten elements, even though | | | more or fewer than ten parenthesized substrings | | | may actually have matched. This has no effect on | | | ereg(3)'s ability to match more substrings. If no | | | matches are found, $regs will not be altered by | | | ereg(3). | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 ereg(3) example The following code snippet takes a date in ISO format (YYYY-MM-DD) and prints it in DD.MM.YYYY format: <?php if (ereg ("([0-9]{4})-([0-9]{1,2})-([0-9]{1,2})", $date, $regs)) { echo "$regs[3].$regs[2].$regs[1]"; } else { echo "Invalid date format: $date"; } ?> NOTES
Note As of PHP 5.3.0, the regex extension is deprecated in favor of the PCRE extension. Calling this function will issue an E_DEPRECATED notice. See the list of differences for help on converting to PCRE. Tip ereg(3) is deprecated as of PHP 5.3.0. preg_match(3) is the suggested alternative to this function. SEE ALSO
eregi(3), ereg_replace(3), eregi_replace(3), preg_match(3), strpos(3), strstr(3), quotemeta(3). PHP Documentation Group EREG(3)
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