Hi Don and thank you so much for answer. I solved. The code posted is used, in that case, as a regular expression for a date in the format YYYY-MM-DD where YYYY is the current year, less the value of the variable {i}.
But now, I have one other issue very very difficult to understand (for me, naturally).
I would know what does mean this code
...
... in particular the two sections | grep -v -e "$echo -n ... and ... sed "s//\\\|g"
Thanks in advance.
PS The code is a command of linux bash script !
Last edited by Scrutinizer; 05-25-2019 at 12:17 PM..
Reason: code tags
Hi,
For my bash script, terminal with bash is generate an OK output and program works right.
already,
terminal with ash have "line 48: syntax error: Bad substitution" output and program don't work.
:confused: (0 Replies)
Hi All,
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# check host value regex='^(||1|2|25)(\.(||1|2|25)){3}$' if ')" != "" ]; then if ]; then echo host $host not found exit 4 fi elif ]; then echo $host is an invalid host address exit 5 fi
espeacailly the top regex part?
---------- Post updated at 06:58 PM ---------- Previous update was... (1 Reply)
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Discussion started by: i4ismail
3 Replies
LEARN ABOUT PHP
ereg
EREG(3) 1 EREG(3)ereg - Regular expression matchSYNOPSIS
int ereg (string $pattern, string $string, [array &$regs])
DESCRIPTION
Searches a $string for matches to the regular expression given in $pattern in a case-sensitive way.
Warning
This function has been DEPRECATED as of PHP 5.3.0. Relying on this feature is highly discouraged.
PARAMETERS
o $pattern
- Case sensitive regular expression.
o $string
- The input string.
o $regs
- If matches are found for parenthesized substrings of $pattern and the function is called with the third argument $regs, the
matches will be stored in the elements of the array $regs. $regs[1] will contain the substring which starts at the first left
parenthesis; $regs[2] will contain the substring starting at the second, and so on. $regs[0] will contain a copy of the complete
string matched.
RETURN VALUES
Returns the length of the matched string if a match for $pattern was found in $string, or FALSE if no matches were found or an error
occurred.
If the optional parameter $regs was not passed or the length of the matched string is 0, this function returns 1.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 4.1.0 | |
| | |
| | Up to (and including) PHP 4.1.0 $regs will be |
| | filled with exactly ten elements, even though |
| | more or fewer than ten parenthesized substrings |
| | may actually have matched. This has no effect on |
| | ereg(3)'s ability to match more substrings. If no |
| | matches are found, $regs will not be altered by |
| | ereg(3). |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
ereg(3) example
The following code snippet takes a date in ISO format (YYYY-MM-DD) and prints it in DD.MM.YYYY format:
<?php
if (ereg ("([0-9]{4})-([0-9]{1,2})-([0-9]{1,2})", $date, $regs)) {
echo "$regs[3].$regs[2].$regs[1]";
} else {
echo "Invalid date format: $date";
}
?>
NOTES
Note
As of PHP 5.3.0, the regex extension is deprecated in favor of the PCRE extension. Calling this function will issue an E_DEPRECATED
notice. See the list of differences for help on converting to PCRE.
Tip
ereg(3) is deprecated as of PHP 5.3.0. preg_match(3) is the suggested alternative to this function.
SEE ALSO eregi(3), ereg_replace(3), eregi_replace(3), preg_match(3), strpos(3), strstr(3), quotemeta(3).
PHP Documentation Group EREG(3)