With the if statement:
if
How can I make it so it accepts a wildcard after the ${CURR_DAY_MONTH} variable?
Putting
a -f /webtrends/SUN/mrw2/access.${CURR_DAY_DAY}${CURR_DAY_MONTH}*
won't work, right? I think I need some kind of special character so it knows the wildcard is... (3 Replies)
Dear all,
i dont know how to split one variable value in 2 variable. please send me any example.
variable1= "abcde developer"
now i want to seperate the values and seperator is space. (6 Replies)
I am new to unix and would appreciate if someone could help.
I have an environment variable SourceFilePath=/db1/Src/test set on the unix server.
I want to expand this SHELL variable in a file using any command sed, awk etc
File contents is as follows:
var=$SourceFilePath/file.txt
... (2 Replies)
Probably a stupid question... how do I use a wildcard in a variable in zsh? If I do:
var=*
echo $var
in bash, it will print all files/directories in the current directory. If I do it in zsh, it will only output an asterisk without the wildcard functionality. Thanks in advance! (1 Reply)
Hi,
I'm using a for loop reading from an input file that contains files, whose path includes a variable name.
But the for loop doesn't expand the variable and therefore can't find the file.
Here's an example:
File BACKUPFILES
/home/John/alpha
/home/Sue/beta... (8 Replies)
I'm trying to make a sed substitution where the substitution pattern is an environment variable to be expanded, but the variable contains a "slash".
sed -e 's/<HOME_DIRECTORY>/'$HOME'/'This gives me the following error:
sed: -e expression #1, char 21: unknown option to `s'Obviously this is... (2 Replies)
Hello,
so i'm making a script, using dynamic variables and trying to expand them. So far it hasn't worked out too well so it seems that I need some help from you, the elite.
Example:
#!/bin/sh
counter=0
until (($counter>5))
counter2=1
until (($counter2>6)); do
if ;... (5 Replies)
Experts,
I want to set value of variables like this in bash shell:
i=5 ; L=100
I want variable d5 (that is d(i) ) to be assign the value of $L ,
d$i=$L ; echo $d5
Not working
Thanks., (3 Replies)
Hello,
Can you please help here?
DAY=$1
MONTH_MONDAY_YEAR = 1 2 3 4
for i in ${MONTH_${DAY}_YEAR}
do
echo ${i}
done
./test.sh MONDAY
./test.sh: line 3: MONTH_MONDAY_YEAR: command not found
./test.sh: line 10: ${MONTH_${DAY}_YEAR}: bad substitution (6 Replies)
I have a lot of files with keywords and unique names. I'm using a shell script to refer to a simple pattern file with comma separated values in order to match on certain keywords. The problem is that I don't understand how to handle the wildcard values when I want to skip over the unique names.
... (5 Replies)
Discussion started by: abercrom
5 Replies
LEARN ABOUT DEBIAN
config::scoped::error
Config::Scoped::Error(3pm) User Contributed Perl Documentation Config::Scoped::Error(3pm)NAME
Config:Scoped::Error - an exception class hierarchy based on Error.pm for Config::Scoped
SYNOPSIS
use Config::Scoped::Error;
Config::Scoped::Error::Parse->throw(
-text => $parser_error,
-file => $config_file,
-line => $thisline,
);
Config::Scoped::Error::IO->throw(
-text => "can't open file: $!",
-file => $config_file,
-line => $thisline,
);
Config::Scoped::Error::Validate::Macro->throw(
-text => "macro redefinition: $macro_name",
-file => $config_file,
-line => $thisline,
);
DESCRIPTION
Config::Scoped::Error is a class hierarchy based on Error.pm. The following Exception class hierarchy is defined:
Config::Scoped::Error
Config::Scoped::Error::Parse
Config::Scoped::Error::Validate
Config::Scoped::Error::Validate::Macro
Config::Scoped::Error::Validate::Parameter
Config::Scoped::Error::Validate::Declaration
Config::Scoped::Error::Validate::Permissions
Config::Scoped::Error::IO
SEE ALSO
Config::Scoped, Error
AUTHOR
Karl Gaissmaier <karl.gaissmaier at uni-ulm.de>
COPYRIGHT AND LICENSE
Copyright (c) 2004-2008 by Karl Gaissmaier
This library is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
perl v5.14.2 2012-03-16 Config::Scoped::Error(3pm)