Sponsored Content
Top Forums UNIX for Beginners Questions & Answers How do I assign the output of a command to a variable within a loop in bash? Post 303033925 by vgersh99 on Sunday 14th of April 2019 04:54:37 PM
Old 04-14-2019
Code:
lnk="$(readlink -f <path> | cut -d '/' -f7)"

 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

how to assign an output to a variable

Hi, I am giving a grep command, and i am getting the output. i want to store it in a variable for eg a = grep '12345' /dir/1/2/log.txt ( the output is number) b= grep 'basic' /dir/1/2/log1.txt (in this case the output is character) so how to assign the output of grep to a variable ... (1 Reply)
Discussion started by: vasikaran
1 Replies

2. Shell Programming and Scripting

Is it possible to re-assign the variable form the loop?

Good day, everyone! I've got a small problem with re-assigning the variable form the loop. What I'm trying to do is: #!/bin/bash/ VAR1="AAA" VAR2="BBB" VAR3="CCC" for WORD in VAR1 VAR2 VAR3; do $WORD="DDD" echo $WORD done :o That's the output and error messages: -bash:... (2 Replies)
Discussion started by: Nafanja
2 Replies

3. Shell Programming and Scripting

Assign bash command to variable

Hi I am trying to write a function that needs to be able to assign the last run shell command to a variable. The actual command string itself not the exit code of the command. I am using the bash command recall ability to do this as follows: alias pb='ps | grep ash' ... (3 Replies)
Discussion started by: Moxy
3 Replies

4. Shell Programming and Scripting

Assign command (with pipe) output to a variable

Hi , I would like to assign command (with pipe) output to a variable. The code is as follows. The goal of the code is to get the last folder folder with a particular name pattern. myDate=`ls | grep 2009 | tail -1` echo "myDate=" $myDate However, in the presence of the pipe, the code... (3 Replies)
Discussion started by: jeff_cen
3 Replies

5. Shell Programming and Scripting

assign awk output to bash variable

greetings all, I am have a heck of a time trying to accomplish a very simple thing. I have an array of "shortname<spaces>id" created from a dscl output. I want to assign shortname=word1 and id=word2. I have tried shortname=$(${textArray} | awk '{print $1}') - and get 'awk : cannot open... (3 Replies)
Discussion started by: macnetdaemon
3 Replies

6. Shell Programming and Scripting

Re-assign variable's value through which FOR LOOP loops

Hi, I've a requirement where I want to re-assign the value in the variable through which FOR LOOP loops. For e.g. Snippet of code --------------- for i in $var do echo $i >> $tempFile var=`echo $another_var | awk -F" " '{print $1}'` done I am re-assigning var so... (2 Replies)
Discussion started by: dips_ag
2 Replies

7. Shell Programming and Scripting

In bash script, how to assign output of a command to a variable while keeping tabs?

Hi, wondering if it's been asked before but didn't find matches from google. Basically I have this line: myvar=$(echo -e "a\tb") Now somehow the '\t' from the echo output gets replaced with white space and then stored in $myvar. It creates a problem for me later to use tab as delimiter to do... (2 Replies)
Discussion started by: birddie
2 Replies

8. Shell Programming and Scripting

Unable to assign command output to variable

Code set -x STATUS="0" echo $STATUS for i in `ls -ltr Report*|awk '{ print $9 }'` do if then flg = "`head -1 "$i" |cut -c 31-33`" echo `head -1 "$i" |cut -c 31-33` echo $flg if then echo "having Fun" STATUS="2" else echo "no Fun" fi fi (2 Replies)
Discussion started by: Funkeydude
2 Replies

9. Shell Programming and Scripting

Assign variable name through loop

Hi As bash does not support multidimensional arrays (?), I need some help with a problem. What I want to do is to assign variable names containing a counter in a loop . what I want to do is basically something like this: #!/bin/bash for i in {1..8}; do var$i = "some command" done... (6 Replies)
Discussion started by: Tobbev
6 Replies

10. UNIX for Dummies Questions & Answers

Need to get a loop variable from output of a command

Hi, I am trying to get a loop counter i and set its value as the ouput of a command: i=`printmo TEST1 | grep -i TEST2 | wc -l` Then I want to use i as counter to run a loop i number of times. Like if i gets a value of 5 I'll have to run loop 5 times. But will i here be a numeric... (3 Replies)
Discussion started by: pat_pramod
3 Replies
MARC::Charset::Code(3pm)				User Contributed Perl Documentation				  MARC::Charset::Code(3pm)

NAME
MARC::Charset::Code - represents a MARC-8/UTF-8 mapping SYNOPSIS
DESCRIPTION
Each mapping from a MARC-8 value to a UTF-8 value is represented by a MARC::Charset::Code object in a MARC::Charset::Table. METHODS
new() The constructor. name() A descriptive name for the code point. marc() A string representing the MARC-8 bytes codes. ucs() A string representing the UCS code point in hex. charset_code() The MARC-8 character set code. is_combining() Returns true/false to tell if the character is a combining character. to_string() A stringified version of the object suitable for pretty printing. char_value() Returns the unicode character. Essentially just a helper around ucs(). marc_value() The string representing the MARC-8 encoding. charset_name() Returns the name of the character set, instead of the code. to_string() Returns a stringified version of the object. marc8_hash_code() Returns a hash code for this Code object for looking up the object using MARC8. First portion is the character set code and the second is the MARC-8 value. utf8_hash_code() Returns a hash code for uniquely identifying a Code by it's UCS value. default_charset_group Returns 'G0' or 'G1' indicating where the character is typicalling used in the MARC-8 environment. get_marc8_escape Returns an escape sequence to move to the Code from another marc-8 character set. charset_value Returns the charset value, not the hex sequence. perl v5.12.4 2010-03-29 MARC::Charset::Code(3pm)
All times are GMT -4. The time now is 10:12 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy