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Full Discussion: Countdown timer with seconds
Operating Systems Linux Ubuntu Countdown timer with seconds Post 303033489 by drew77 on Saturday 6th of April 2019 11:08:41 AM
Old 04-06-2019
Countdown timer with seconds

I would like this to work with seconds as well.

Code:
#!/bin/bash
# 
 
if [ "$#" -lt "2" ] ; then 
    echo "Incorrect usage ! Example:" 
    echo './CountDown.sh -d  "Jun 10 2011 16:06"' 
    echo 'or' 
    echo './CountDown.sh -m  90' 
    exit 1 
fi 
 
now=`date +%s` 
 
if [ "$1" = "-d" ] ; then 
    until=`date -d "$2" +%s` 
    sec_rem=`expr $until - $now` 
    echo "-d" 
    if [ $sec_rem -lt 1 ]; then 
        echo "$2 is already history !" 
    fi 
fi 
 
if [ "$1" = "-m" ] ; then 
    until=`expr 60 \* $2` 
    until=`expr $until + $now` 
    sec_rem=`expr $until - $now` 
    echo "-m" 
    if [ $sec_rem -lt 1 ]; then 
        echo "$2 is already history !" 
    fi 
fi 
 
_R=0
_C=7
tmp=0
percent=0
total_time=0
col=`tput cols`
col=$[ $col -5 ]

while [ $sec_rem -gt 0 ]; do 
    clear 
    date 
    let sec_rem=$sec_rem-1 
    interval=$sec_rem 
    seconds=`expr $interval % 60` 
    interval=`expr $interval - $seconds` 
    minutes=`expr $interval % 3600 / 60` 
    interval=`expr $interval - $minutes` 
    hours=`expr $interval % 86400 / 3600` 
    interval=`expr $interval - $hours` 
    days=`expr $interval % 604800 / 86400` 
    interval=`expr $interval - $hours` 
    weeks=`expr $interval / 604800` 
    echo "----------------------------" 
    echo "Seconds: " $seconds 
    echo "Minutes: " $minutes 
    echo "Hours:   " $hours 
    echo "Days:    " $days 
    echo "Weeks:   " $weeks 

    echo -n "["

    progress=$[$progress + 1]
    if [ $total_time -lt 1 ] ; then
        total_time=$[$hours * 3600 + $minutes * 60 + $seconds]
    fi
    
    printf -v f "%$(echo $_R)s>" ; printf "%s\n" "${f// /=}"
    _C=7
    tput cup 7 $col

    tmp=$percent
    percent=$[$progress * 100 / $total_time]
    printf "]%d%%" $percent
    change=$[$percent - $tmp]

    _R=$[ $col * $percent / 100 ]

    sleep 1
done
printf "\n"

 

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EXPR(1) 						      General Commands Manual							   EXPR(1)

NAME
expr - evaluate arguments as an expression SYNOPSIS
expr arg ... DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is a separate argument. The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped. expr | expr yields the first expr if it is neither null nor `0', otherwise yields the second expr. expr & expr yields the first expr if neither expr is null or `0', otherwise yields `0'. expr relop expr where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if both expr are integers, otherwise lexicographic. expr + expr expr - expr addition or subtraction of the arguments. expr * expr expr / expr expr % expr multiplication, division, or remainder of the arguments. expr : expr The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the matching operator yields the number of characters matched (`0' on failure). ( expr ) parentheses for grouping. Examples: To add 1 to the Shell variable a: a=`expr $a + 1` To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/': expr $a : '.*/(.*)' '|' $a Note the quoted Shell metacharacters. SEE ALSO
sh(1), test(1) DIAGNOSTICS
Expr returns the following exit codes: 0 if the expression is neither null nor `0', 1 if the expression is null or `0', 2 for invalid expressions. 7th Edition April 29, 1985 EXPR(1)
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