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Top Forums Programming Why does this example C code run and yet SHOULD either not compile or give a segmentation fault? Post 303033007 by Corona688 on Thursday 28th of March 2019 11:10:36 AM
Old 03-28-2019
Why should your first program crash? You're not touching any memory you shouldn't, and one "ret" is as good as another as long as you've got the same size stack context, which you do to the last byte.
 

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OUTB(2) 						     Linux Programmer's Manual							   OUTB(2)

NAME
outb, outw, outl, outsb, outsw, outsl, inb, inw, inl, insb, insw, insl, outb_p, outw_p, outl_p, inb_p, inw_p, inl_p - port I/O DESCRIPTION
This family of functions is used to do low-level port input and output. The out* functions do port output, the in* functions do port input; the b-suffix functions are byte-width and the w-suffix functions word-width; the _p-suffix functions pause until the I/O completes. They are primarily designed for internal kernel use, but can be used from user space. You compile with -O or -O2 or similar. The functions are defined as inline macros, and will not be substituted in without optimization enabled, causing unresolved references at link time. You use ioperm(2) or alternatively iopl(2) to tell the kernel to allow the user space application to access the I/O ports in question. Failure to do this will cause the application to receive a segmentation fault. CONFORMING TO
outb() and friends are hardware-specific. The value argument is passed first and the port argument is passed second, which is the opposite order from most DOS implementations. SEE ALSO
ioperm(2), iopl(2) COLOPHON
This page is part of release 3.27 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/. Linux 1995-11-29 OUTB(2)
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