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Top Forums Shell Programming and Scripting Script to replace a string with pattern read from a file Post 303031960 by RudiC on Friday 8th of March 2019 06:06:06 AM
Old 03-08-2019
Try double quotes in lieu of single quotes to enable shell's "variable expansion".


EDIT: But, there's more to comment on. Your sed command doesn't have a file to operate on, the goal of the script is not quite clear, and in general there are some coding improvement opportunities.
Do you want to operate on the files listed in "blocks.txt", or do you just want the single file "rules.txt" to be modified?

Last edited by RudiC; 03-08-2019 at 07:15 AM..
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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