I do ls -l ABC*, I get arg list too long message. This will not happen if ABC* has small no of files I believe 4000 files is limit. Any way of avoiding this.
I even tried like this
for i in `ls -l ABC*`
do
echo $i
done
Same problem.
Any solution would be great.
I am on HP-UX... (5 Replies)
echo dirname/filename* | xargs ls -t
As a substitute doesn't give the results desired when I exceed the buffer size. I still want the files listed in chronological order, unfortunately xargs releases the names piecemeal...does anyone have any ideas? :( (4 Replies)
hello all
i need some help because i am a unix/linux dummy...i have the following:
DIR1> has 121437 files in it with varying dates going back to early April,
a sub dir DIR1/DIR2> has 55835 files in it
I need to move all files (T*.*) out of DIR1 into DIR2 that are older than today?
Ive been... (2 Replies)
Hi,
I am trying to perform this task:
tar -cvf tar.newfile ??????.bas
I got error "arg list too long". Is ther any way around? I have about 1500 file need to be tar together.
Thanks in advance (5 Replies)
Hey guys. I have a program written in which i am trying to get the files from one remote machine and transferring the files to another remote machine using SCP.
It works fine for 50 or 60 files but when the files grows to 250 then i get an error message stating "Arg list too long".
#scp -p... (5 Replies)
Hi,
Help. I have a file that contains a list of users in a file. I want to cat the content of the file and feed it into sed to a preformated report. The error I got is "ksh: /usr/bin/sed: arg list too long" My method below.
A=`cat FILE1.txt`
B=`echo $A`
sed "s#USERLIST#$B#" FILE2 >... (2 Replies)
Hello,
I'm trying to search through 30,000 files in 1 directory, and am getting the "arg list too long" error. I've searched this forum and have been playing around with xargs and can't get that to work either. I'm using ksh on Solaris.
Here's my original code:
nawk "/Nov 21/{_=2}_&&_--"... (14 Replies)
Hello All,
I am trying to find a file name with .sh exention from a list of .dat files inside a directory.
find /app/folder1/* -name '*.dat'| xargs grep '.sh'
ksh: /usr/local/bin/find: arg list too long
Please help me finding the command.
Thanks (3 Replies)
Discussion started by: tkhan9
3 Replies
LEARN ABOUT DEBIAN
bup-join
bup-join(1) General Commands Manual bup-join(1)NAME
bup-join - concatenate files from a bup repository
SYNOPSIS
bup join [-r host:path] [refs or hashes...]
DESCRIPTION
bup join is roughly the opposite operation to bup-split(1). You can use it to retrieve the contents of a file from a local or remote bup
repository.
The supplied list of refs or hashes can be in any format accepted by git(1), including branch names, commit ids, tree ids, or blob ids.
If no refs or hashes are given on the command line, bup join reads them from stdin instead.
OPTIONS -r, --remote=host:path
Retrieves objects from the given remote repository instead of the local one. path may be blank, in which case the default remote
repository is used. The connection to the remote server is made with SSH. If you'd like to specify which port, user or private key
to use for the SSH connection, we recommend you use the ~/.ssh/config file.
EXAMPLE
# split and then rejoin a file using its tree id
TREE=$(tar -cvf - /etc | bup split -t)
bup join $TREE | tar -tf -
# make two backups, then get the second-most-recent.
# mybackup~1 is git(1) notation for the second most
# recent commit on the branch named mybackup.
tar -cvf - /etc | bup split -n mybackup
tar -cvf - /etc | bup split -n mybackup
bup join mybackup~1 | tar -tf -
SEE ALSO bup-split(1), bup-save(1), ssh_config(5)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-join(1)
02-28-2019
