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Top Forums Shell Programming and Scripting Help building a variable string from a keyword - character replacements! Post 303031098 by ghaniba on Thursday 21st of February 2019 01:28:43 PM
Old 02-21-2019
Quote:
Originally Posted by Chubler_XL
Another approach using substr:
Wow, that's amazing, exactly what I was after. Since my skills are soo feeble, could I trouble you for one more enhancement? In that same KEYWORDS string, I'd like to do a single character replacement as well, with a single % marching through, so it would look like this?

Code:
KEYWORD="%ominos d%minos do%inos dom%nos domi%os domin%s domino% __minos _o_inos _om_nos _omi_os _omin_s _omino_ d__inos d_m_nos d_mi_os d_min_s d_mino_ do__nos do_i_os do_in_s do_ino_ dom__os dom_n_s dom_no_ domi__s domi_o_ domin__"

I did give a solid hour trying to tinker with the awk -- but I'm just not skilled enough not to shatter the loop. HAHA!

Thanks again for your efforts, its amazing to see how much I don't know!

Dave aka Ghan
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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