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Help building a variable string from a keyword - character replacements!

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# 1  
Old 02-19-2019
Help building a variable string from a keyword - character replacements!

Hello scripting geniusii! I come to kneel before the alter of your wisdom!

I am looking to take a keyword and replace characters within that keyword and add them to a string variable. I would like this to only go through however many characters the word has, which may vary in size.

Example word - dominos:
$ echo "dominos" |  sed 's/./_/1; s/./_/2'
$ echo "dominos" |  sed 's/./_/1; s/./_/3'
$ echo "dominos" |  sed 's/./_/1; s/./_/4'
$ echo "dominos" |  sed 's/./_/1; s/./_/5'
$ echo "dominos" |  sed 's/./_/1; s/./_/6'
$ echo "dominos" |  sed 's/./_/1; s/./_/7'
$ echo "dominos" |  sed 's/./_/2; s/./_/3'
$ echo "dominos" |  sed 's/./_/2; s/./_/4'
$ echo "dominos" |  sed 's/./_/2; s/./_/5'
$ echo "dominos" |  sed 's/./_/2; s/./_/6'
$ echo "dominos" |  sed 's/./_/2; s/./_/7'

In the end state, I would like it to look like this:
KEYWORD="__minos _o_inos _om_nos _omi_os _omin_s _omino_ d__inos d_m_nos d_mi_os d_min_s ... "

I am doing this today manually, creating my "KEYWORD" variable, but I'm trying to tidy this all up and make my script pull the current working directory and use that as the keyword variable base, so that my script can be standardized over several different keywords I'm working with.

Hope this makes some sense, and Thanks so much in advance for your thoughts!

Dave aka Ghan
# 2  
Old 02-19-2019
what OS are you under?
Do you have gawk?
here's something to start with: echo 'dominos' | gawk -f gh.awk
where gh.awk is:
  for (i=1;i<=len;i++)
      print gensub(".", "_", i, gensub(".", "_", j, $0))

Last edited by vgersh99; 02-19-2019 at 05:23 PM..
These 2 Users Gave Thanks to vgersh99 For This Post:
# 3  
Old 02-20-2019
I'm just using a little utility Ubuntu box. Nothing special!


Dave aka Ghan
# 4  
Old 02-20-2019
Originally Posted by ghaniba
I'm just using a little utility Ubuntu box. Nothing special!


Dave aka Ghan
Ok, thanks!
# 5  
Old 02-20-2019
Another approach using substr:

awk '
  printf "KEYWORD=\""
  for (i=0; i <= length($0) - 2; i++)
    for(j=i + 1; j <= length($0) - 1; j++)
      printf "%s%s", \
          substr($0, 0, i) "_"  \
          substr($0, i + 2, j - i - 1) "_"  \
          substr($0, j + 2),  \
          i == (length($0) - 2) ? "\"" : " "
   print ""

Last edited by Chubler_XL; 02-20-2019 at 10:50 PM..
# 6  
Old 02-21-2019
Originally Posted by Chubler_XL
Another approach using substr:
Wow, that's amazing, exactly what I was after. Since my skills are soo feeble, could I trouble you for one more enhancement? In that same KEYWORDS string, I'd like to do a single character replacement as well, with a single % marching through, so it would look like this?

KEYWORD="%ominos d%minos do%inos dom%nos domi%os domin%s domino% __minos _o_inos _om_nos _omi_os _omin_s _omino_ d__inos d_m_nos d_mi_os d_min_s d_mino_ do__nos do_i_os do_in_s do_ino_ dom__os dom_n_s dom_no_ domi__s domi_o_ domin__"

I did give a solid hour trying to tinker with the awk -- but I'm just not skilled enough not to shatter the loop. HAHA!

Thanks again for your efforts, its amazing to see how much I don't know!

Dave aka Ghan
# 7  
Old 02-21-2019

KEYWORD=$(echo "$word" | awk ' {
  for (i=1; i<=length; i++)
    printf "%s", substr($0, 1, a++) b substr($0, a+1) FS;
  for (j=length; j>1; j--)
   for (i=1; i<j; i++)
    printf "%s", substr($0, 1, length - j) c substr($0, length - j + 2, i-1) c substr($0, (i + length - j + 2)); FS;
  print "";
}' b="%" c="_"

echo "$KEYWORD"

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