10-24-2018
You can calculate seconds from HH:MM:SS via seconds+(minutes*60)+(hours*60*60)
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1. Programming
Hi All,
Urgent! Just a newbie needing advice.
Has anybody have a sample C script code in Unix to display time with milliseconds?
Most of the research I'm doing is up to the seconds format only.
Thanks!
Leidail (3 Replies)
Discussion started by: rezlez
3 Replies
2. Shell Programming and Scripting
Hi,
I have a log file that has the date in this format "2006-05-30_13:14:04,256". I need to find the time difference between two log entries in milliseconds.
How to achieve this in AWK/GAWK script? :confused: (2 Replies)
Discussion started by: omprasad
2 Replies
3. Shell Programming and Scripting
Hope somebody is happy.
NR==1 {
num_columns=split( $0, menuend );
next;
}
{
split( $0, substrend );
for ( i=1; i<=NF; i++ ) {
minuend -= substrend;
}
}
END {
print "Result:";
for ( i=1; i<=num_columns; i++ ) {
printf(... (3 Replies)
Discussion started by: awkward
3 Replies
4. Shell Programming and Scripting
Hi Folks
I have tried awk command to conditionally add or subtract value from specific row in a file. The test file looks like:
# cat test.txt
cont x y
Max 0.3 0.9
Min 0.2 0.9
diff 0.1 0
# awk '{for (i=2; i <=NF; i++) if ($i== "0") $i=$i+0.2; print}' test.txt
Output:
cont... (1 Reply)
Discussion started by: dixits
1 Replies
5. Shell Programming and Scripting
Hi All,
could any body let me know.
how to get timestamp with millisecond precision in unix bash shell.
example -->2005-12-06- 4-22-35-195
please help me.
Thanks,
Krupa:wall: (3 Replies)
Discussion started by: krupasindhu18
3 Replies
6. Shell Programming and Scripting
I have two files with similar column pattern as given below :
2 sample lines from file1 are given below.
18 12630 . G T 49.97 . AC=2;AF=1.00;AN=2;DP=3;Dels=0.00;FS=0.000;HRun=0;HaplotypeScore=0.0000;MQ=60.00;MQ0=0;NDA=1;QD=16.66;SB=-0.01 GT:AD:DP:GQ:PL ... (2 Replies)
Discussion started by: vaibhavvsk
2 Replies
7. Shell Programming and Scripting
Hi,
I am using the following code to fetch lines that are generated in last 1 hr . Hence, I am using date function to calculate -last 1 hr & the current hr and then somehow use awk (or sed-if someone could guide me better)
with some regex pattern.
dt_1=`date +%h" "%d", "%Y\ %l -d "1 hour... (10 Replies)
Discussion started by: sarah-alikhan31
10 Replies
8. UNIX for Dummies Questions & Answers
---------- Post updated at 01:58 PM ---------- Previous update was at 01:48 PM ----------
For some reason my question is not getting printed. Here are the details:
Greetings.
I would like to add/subtact an integer to/from two columns of integers. I feel like this should be easy using awk... (3 Replies)
Discussion started by: Twinklefingers
3 Replies
9. Shell Programming and Scripting
data.txt:
0,mq_conn_open_error,1444665949,734,/PROD/G/cicsitlp/sys/unikixmain.log,64K,mq_conn_open_error,62022,0,733--734
0,mq_conn_open_error,1444666249,734,/PROD/G/cicsitlp/sys/unikixmain.log,64K,mq_conn_open_error,62022,0,734--734... (7 Replies)
Discussion started by: SkySmart
7 Replies
10. HP-UX
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT SUSE
time::seconds
Time::Seconds(3pm) Perl Programmers Reference Guide Time::Seconds(3pm)
NAME
Time::Seconds - a simple API to convert seconds to other date values
SYNOPSIS
use Time::Piece;
use Time::Seconds;
my $t = localtime;
$t += ONE_DAY;
my $t2 = localtime;
my $s = $t - $t2;
print "Difference is: ", $s->days, "
";
DESCRIPTION
This module is part of the Time::Piece distribution. It allows the user to find out the number of minutes, hours, days, weeks or years in a
given number of seconds. It is returned by Time::Piece when you delta two Time::Piece objects.
Time::Seconds also exports the following constants:
ONE_DAY
ONE_WEEK
ONE_HOUR
ONE_MINUTE
ONE_MONTH
ONE_YEAR
ONE_FINANCIAL_MONTH
LEAP_YEAR
NON_LEAP_YEAR
Since perl does not (yet?) support constant objects, these constants are in seconds only, so you cannot, for example, do this: "print
ONE_WEEK->minutes;"
METHODS
The following methods are available:
my $val = Time::Seconds->new(SECONDS)
$val->seconds;
$val->minutes;
$val->hours;
$val->days;
$val->weeks;
$val->months;
$val->financial_months; # 30 days
$val->years;
The methods make the assumption that there are 24 hours in a day, 7 days in a week, 365.24225 days in a year and 12 months in a year.
(from The Calendar FAQ at http://www.tondering.dk/claus/calendar.html)
AUTHOR
Matt Sergeant, matt@sergeant.org
Tobias Brox, tobiasb@tobiasb.funcom.com
BalieXXzs SzabieXX (dLux), dlux@kapu.hu
LICENSE
Please see Time::Piece for the license.
Bugs
Currently the methods aren't as efficient as they could be, for reasons of clarity. This is probably a bad idea.
perl v5.12.1 2010-04-26 Time::Seconds(3pm)