Subtract millisecond Timestamps with awk Post: 303025102

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current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error...

LEARN ABOUT HPUX

whodo

whodo(1M)																 whodo(1M)

NAME

       whodo - which users are doing what

SYNOPSIS

DESCRIPTION

       The command produces merged, reformatted, and dated output from the and commands (see who(1) , ps(1) and acctcom(1M)).

       If user is specified, output is restricted to all sessions pertaining to that user.

       The following options are available:

       Suppress the heading.

       Produce a long form of output.  The fields displayed
		      are:  the  user's login name, the name of the tty the user is on, the time of day the user logged in (in hours:minutes), the
		      idle time - that is, the time since the user last typed anything (in hours:minutes), the CPU time used by all processes  and
		      their  children  on that terminal (in minutes:seconds), the CPU time used by the currently active processes (in minutes:sec-
		      onds), and the name and arguments of the current process.

EXTERNAL INFLUENCES

   Environment Variables
       determines the order in which the output is sorted.

       If is not specified in the environment or is set to the empty string, the value of is used as a default.  If is not specified or is set	to
       the  empty  string,  a  default of ``C'' (see lang(5)) is used instead of If any internationalization variable contains an invalid setting,
       behaves as if all internationalization variables are set to ``C'' (see environ(5)).

FILES

       SEE ALSO
	      ps(1), who(1), acctcom(1M).

STANDARDS CONFORMANCE

																	 whodo(1M)

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