Does any one know how to get a recursive directory listing in long format (showing owner, group, permission etc) without listing the files contained in the directories.
The following command also shows the files but I only want to see the directories.
ls -lrtR * (4 Replies)
Hi,
I need a help. I want to see all the files in the directory with the Time Stamp. I use the following command.
$ls -lt
This displays the files with time stamp, but not all the files. Only last few months, the files are displayed with timestamp, the old files are only have dates.
... (2 Replies)
Is there a way of listing everything under a directory.
So for example if you wanted to know everything under the USR directory you would get all the sub directories and files in those directories as well as the file directly under the USR directory. I would imagine that you could do this... (5 Replies)
Hai friends is there any command in unix that display only directories...
(I have 5 directories in my home directory, and i also have some files along with directories...But when i tried to show the directory listing using the command ls -d i wasn't presented by the directory listing...Please... (2 Replies)
Hi,
example of Unix / Linux dialog utility is below.
I am going to use dialog as simple GUI for testing of a modem.
So I need to combine some dialog boxes into one.
I need to have input box, output box, info box, dialog box,
radiobox as in any standard program with graphical user... (2 Replies)
i have searched through this site and have found some useful information but i'm struggling with one thing. In my script i am created a start and end file so I can get a listing of the files within those two files. However I want to exclude any sub-directories in this listing. Below are the... (8 Replies)
Hi,
I have a directory with a bunch of files say around 150K.
I want the directory's path and the filenames printed to a text file.
Example:
If I am in the directory /path/test and the files in this directory are
My output file should be like this
Thanks in advance
----------... (4 Replies)
Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted!
1. The problem statement, all variables and given/known data:
A script that takes any number of directories as command line arguments and then lists the contents of each of... (3 Replies)
Hello,
I'm trying to build a small script to store a command into a dynamic variable, and I have trouble assigning the variable.
#!/bin/bash
declare -a var1array=("value1" "value2" "value3")
var1arraylength=${#var1array}
for (( i=1; i<${var1arraylength}+1; i++ ));
do
mkdir... (7 Replies)
Hello.
Any help would be greatly appreciated.
Right now I have the following input box that works fine and well, however I would like to wrap this is a loop that requires input. Right now the script will happily continue on if the user just hits enter. I'd like to require a minimum of a 5... (5 Replies)
Discussion started by: woodson2
5 Replies
LEARN ABOUT LINUX
shtool-path
SHTOOL-PATH.TMP(1) GNU Portable Shell Tool SHTOOL-PATH.TMP(1)NAME
shtool-path - GNU shtool command dealing with shell path variables
SYNOPSIS
shtool path [-s|--suppress] [-r|--reverse] [-d|--dirname] [-b|--basename] [-m|--magic] [-p|--path path] str [str ...]
DESCRIPTION
This command deals with shell $PATH variables. It can find a program through one or more filenames given by one or more str arguments. It
prints the absolute filesystem path to the program displayed on "stdout" plus an exit code of 0 if it was really found.
OPTIONS
The following command line options are available.
-s, --suppress
Supress output. Useful to only test whether a program exists with the help of the return code.
-r, --reverse
Transform a forward path to a subdirectory into a reverse path.
-d, --dirname
Output the directory name of str.
-b, --basename
Output the base name of str.
-m, --magic
Enable advanced magic search for ""perl"" and ""cpp"".
-p, --path path
Search in path. Default is to search in $PATH.
EXAMPLE
# shell script
awk=`shtool path -p "${PATH}:." gawk nawk awk`
perl=`shtool path -m perl`
cpp=`shtool path -m cpp`
revpath=`shtool path -r path/to/subdir`
HISTORY
The GNU shtool path command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 1998 for Apache. It was later taken
over into GNU shtool.
SEE ALSO shtool(1), which(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-PATH.TMP(1)