Thanks for looking into it. I executed the script you provided but ended up with some errors. It might be a formatting error from my side, since I am pretty new to Unix/Perl. This is what I got:
Hi,
I have a file say abc. I get the timestamp in following way:
ls -ltr abc | awk -F" " '{print $6,$7,$8}'
Mar 8 10:23
I need to get the timestamp as :
03-08-2007 10:23:00
Thanks
Sumeet (1 Reply)
hi everyone, im new here and am in desperate need of help. I want to convert my 32 bit unix time stamp ' 45d732f6' into a readable format (Sat, 17 February 2007 16:53:10 UTC) using c++.
I have looked around the interent but i just cant make sense of anything. All examples i can find just... (3 Replies)
Hi All,
I have a string like below.
"Mar 31 2009" .
I want to convert this to unix time .
Also please let me know how to find the unix time for the above string minus one day. For Eg. if i have string "Mar 31 2009" i want to find the unix time stamp of "Mar 30 2009".
Thanks in advance,... (11 Replies)
Hello,
How do I convert unix timestamp value to 'normal' date format - to get year month and day values ?
Looks like it's easy to do using GNU date (linux systems). But how do I do tthis on AIX ?
I don't want to write C program, any ways to do that using unix shells ?
thanks (1 Reply)
Hello Experts,
I have a timestamp(6) column in a .csv data file , format of the data is as below:-
ETCT,P,Elec, Inc.,abc,11/5/2010 4:16:09.000000 PM,Y,Y,Y
I want the timestamp column to be properly formatted like
11/05/2010 04:16:09.000000 PM
Currently the "0" is missing with... (3 Replies)
Hi all,
I'm a Unix newbie and I need to get file timestamp in the following format:
YYYYMMDD HH24:MM:SS
example:
20120713 18:49:30
For start I've tried the following code, but I don't know how to display the year and even format the date:
ls -l $filename | awk '{print $7 $6 $8}'
My... (4 Replies)
Hello I have a file : file1.txt with the below contents :
237176 test1 test2 1442149024
237138 test3 test4 1442121300
237171 test5 test7 1442112823
237145 test9 test10 1442109600
In the above file fourth field represents the timestamp in Unix format.
I found a command which converts... (6 Replies)
Hello All,
I have a date in DD/MM/YYYY format. I am trying to convert this into unix timestamp. I have tried following:
date -d $mydate +%s
where mydate = 23/12/2016 00:00:00
I am getting following error:
date: extra operand `+%s'
Try `date --help' for more information.
... (1 Reply)
Discussion started by: angshuman
1 Replies
LEARN ABOUT MOJAVE
time::localtime
Time::localtime(3pm) Perl Programmers Reference Guide Time::localtime(3pm)NAME
Time::localtime - by-name interface to Perl's built-in localtime() function
SYNOPSIS
use Time::localtime;
printf "Year is %d
", localtime->year() + 1900;
$now = ctime();
use Time::localtime;
use File::stat;
$date_string = ctime(stat($file)->mtime);
DESCRIPTION
This module's default exports override the core localtime() function, replacing it with a version that returns "Time::tm" objects. This
object has methods that return the similarly named structure field name from the C's tm structure from time.h; namely sec, min, hour, mday,
mon, year, wday, yday, and isdst.
You may also import all the structure fields directly into your namespace as regular variables using the :FIELDS import tag. (Note that
this still overrides your core functions.) Access these fields as variables named with a preceding "tm_" in front their method names.
Thus, "$tm_obj->mday()" corresponds to $tm_mday if you import the fields.
The ctime() function provides a way of getting at the scalar sense of the original CORE::localtime() function.
To access this functionality without the core overrides, pass the "use" an empty import list, and then access function functions with their
full qualified names. On the other hand, the built-ins are still available via the "CORE::" pseudo-package.
NOTE
While this class is currently implemented using the Class::Struct module to build a struct-like class, you shouldn't rely upon this.
AUTHOR
Tom Christiansen
perl v5.18.2 2013-11-04 Time::localtime(3pm)